Section D: A research team believes that the systolic blood pressure of adult males is normally distributed with apopulation variance equal to 400. A simple random sample of 36 males selected from the adult male population had amean systolic blood pressure reading of 130. Let u denote the mean systolic blood pressure of adult males. Suppose theresearch team wants to test, at the 5% level of significance, whether the mean systolic blood pressure of adult males isnot equal to 135. Suppose the assumptions of this hypothesis test are satisfied. 13. What are the null and alternative hypotheses, and level of significance for the hypothesis test stated in the preambleof Section D?H₁ : μ = 135 vs H₁ : µ > 135 (a = 0.05)○ H₁ μ =135 vs Ha : µ < 135 (a = 0.05)Ο Ηo : μ=135 vs H₁ : μ ‡ 135(α = 0.05)H₁ : μ = 0 vs Ha : μ‡0 (α = 0.05)

Answered: Image /qna-images/answer/a5b05238-075c-443d-8fb1-b1d5a6166f39.jpg

Answered: 13. What are the null and alternative…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test whether patients getting Treatment 1 are more likely to survive, if 63 out of 83 getting Treatment 1 survive and 30 out of 68 getting Treatment 2 survive. (a) Find the relevant sample proportions in each group and the pooled proportion. Round your answers to three decimal places. P₁ 122 P₂ P = || =
6
Suppose you are carrying out the a hypothesis test at the a = 0.04 level with the following set of hypotheses: Hou = 10 Ha µ > 10 Assuming that all of the relevant assumptions were met and you ended up with a p-value of 0.39, what would you make as your decision for this hypothesis test?
Test the claim about the population mean, µ, at the given level of significance using the given sample statistics. Claim: µ ‡6000; α = 0.04; ∞ = 416. Sample statistics: x = 5700, n = 38 μ Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: μ = 6000 H₂: μ#6000 'a O C. Ho: μ ≥6000 Ha: μ#6000 E. Ho: μ#6000 Ha: μ ≤ 6000 B. Ho: μ#6000 H₂: μ = 6000 O D. Ho: μ6000 H₂:μ ≥6000 OF. Ho: μ≤ 6000 Ha: μ#6000
18.
4. State the null and alternative hypotheses, state whether left/right/two-tailed, state a, find the P-Value, should we reject Ho, or should we fail to reject Ho at 1% level of significance? Use the P-Value method only, not the critical value method. Example: The test statistic of z = -1.5 is obtained when testing the claim that ua Careful: This example is for a z-value problem, the actual questilons in #4 use t-values. a. The claim is that for 12 AM body temperatures, the mean is u<98 F. The size is n=5 and the test statistic is 1=-1.603. b. The claim is that for Verizon data speeds at airports, the mean is u=14.00 mbps . The size is n=14 and the test statistic is 1=-2.645.
The claim is that for 10 AM body temperatures of males, the mean is less than 98.6°F. The sample size is n=39 and the test statistic is t=−4.041. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. Question content area bottom Part 1 State the null and alternative hypotheses. H0: μ ▼ greater than> less than< not equals≠ equals= enter your response here H1: μ ▼ greater than> less than< less than or equals≤ not equals≠ equals= greater than or equals≥ enter your response here (Type integers or decimals. Do not round. Do not include the degree symbol in your answer.) Part 2 The test statistic is enter your response here. (Round to two decimal places as needed.) Part 3 The P-value is enter your response here. (Round to three decimal places as needed.) Part 4 Based on the P-value, there ▼ is is not sufficient evidence at a significance level of 0.01 to…
A random sample of 510 observations produced a sample proportion equal to 0.33. Find the critical and observed values of z for the following test of hypotheses using α = 0.01 . H 0 : p = 0.30 versus H 1 : p ≠ 0.30 . Round your answers to two decimal places. zcritical left =Enter your answer; z_critical left zcritical right =Enter your answer; z_critical right zobserved =Enter your answer; z_observed
i need to get the answer for Za
16. According to a food website, the mean consumption of popcorn annually by Americans division of the food website unleashes an aggressive campaign designed to get Americans to consume even more popcorn. Complete parts (a) through (c) below. 63 quarts. The marketing (a) Determine the null and alternative hypotheses that would be used to test the effectiveness of the marketing campaign. (1) (2) Ho: (3) (4) H1: (Type integers or decimals. Do not round.) (b) A sample of 895 Americans provides enough evidence to conclude that marketing campaign was effective. Provide a statement that should be put out by the marketing department. O A. There is not sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. O B. There is not sufficient evidence to conclude that the mean consumption of popcorn has risen. O C. There is sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. O D. There is sufficient evidence to conclude that the…
Suppose that we need to compute the probability of Type II error and the power for the following hypothesis test: Ho: μ = 5 and H1: μ > 5 with the following decision rule: reject Ho if [-5]/[0.1/] > 1.645 or 5 + 1.645*[0.1/] = 5.041, when we know that the true population mean is given by μ = 5.15. Then the solution should proceed as follows: Since μ = 5.15, β = P(≤xc| μ = μ*) = P(≤5.041| μ*=5.15) = P([5.15 - 5.041]//[0.1/] = P(z≤1.05) and the power of the test is given by power = 1 – .0111 = .899. Is it true or false? Note that xc is thecritical value from the appropriate sampling distribution of the sample mean, μ is the population mean under null hypothesis, μ * is the true population mean, and x-bar is the sample mean. True False
According to a leasing firm's reports, the mean number of miles driven annually in its leased cars is 13,600 miles with a standard deviation of 2820 miles. The company recently starting using new contracts which require customers to have the cars serviced at their own expense. The company's owner believes the mean number of miles driven annually under the new contracts, u, is less than 13,600 miles. He takes a random sample of 50 cars under the new contracts. The cars in the sample had a mean of 13,499 annual miles driven. Is there support for the claim, at the 0.10 level of significance, that the population mean number of miles driven annually by cars under the new contracts, is less than 13,600 miles? Assume that the population standard deviation of miles driven annually was not affected by the change to the contracts. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified…

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