Provide an appropriate response. The mean age of judges in Dallas is greater than 58.7 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis? There is not sufficient evidence to support the claim μ > 58.7. There is sufficient evidence to reject the claim µ > 58.7. There is not sufficient evidence to reject the claim μ > 58.7. There is sufficient evidence to support the claim μ > 58.7.
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- A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.6 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim. Hypothesis test results: μ: Mean of variable Ho: μ=2.6 HA H>2.6 Variable Sample Mean Length 2.75311 Std. Err. DF T-Stat 0.274284 399 0.558217 P-value 0.2885 OA. Fail to reject Ho. There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles OB. Reject Ho. There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles OC. Reject Ho. There is not sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles. OD. Fail to reject Ho. There is not sufficient evidence to support…A magazine reported that at the top 50 business schools in a region, students studied an average of 12.5 hours. Set up a hypothesis test to try to prove that the mean number of hours studied at your school is different from the reported 12.5 hour benchmark. Complete parts (a) through (c) below. Question content area bottom Part 1 a. State the null and alternative hypotheses. Choose the correct answer below. A. H0: α=12.5 H1: β≠12.5 B. H0: α≠12.5 H1: α=12.5 C. H0: α=12.5 H1: α≠12.5 D. H0: μ=12.5 H1: X≠12.5 E. H0: μ≠12.5 H1: X=12.5 F. H0: β≠12.5 H1: β=12.5 G. H0: μ=12.5 H1: μ≠12.5 H. H0: X=12.5 H1: X≠12.5 I. H0: α≠12.5 H1: β=12.5 J. H0: X≠12.5 H1: X=12.5 K. H0: μ≠12.5 H1: μ=12.5 L. H0: β=12.5 H1: β≠A data set includes data from 400 random tornadoes. The display from the technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.1 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Hypothesis test results: μ : Mean of variable H0 : μ=2.1 HA : μ>2.1 Variable Sample Mean Std. Err. DF T-Stat P-value Length 2.63613 0.288165 399 1.860497 0.0318 p Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses
- The CEO of a popular company claims that the mean response time for customer service calls is 9 minutes. A group of recent customers believes that the mean response time is actually slower than that, meaning it takes more than 9 minutes. The customers wish to conduct a hypothesis test at the a = 0.05 level of significance to determine if their claim that it is slower is correct. Which would be correct hypotheses for such a test? Ho:u = 9, Hị: µ > 9 Ho:4 + 9, Hị: µ = 9 %3D OHo:H < 9, Hị :H = 9 ΘΗ :μ = 9, Η :μ <9 ΘΗ:μ = 9, Η :μέ9 What does the P-value measure? O The power of mind of the statistician who performed the statistical experiment O The probability that the alternate hypothesis is true The probability that the results of a statistical experiment are due only to chance O The probability that the results of an statistical experiment are due to something more significant than chance If the resulting P-value is 0.065, which would be the appropriate conclusion? There is significant…You are a researcher verifying the claim that the average adult consumes 1.7 cups of coffee per day. The population standard deviation is 0.5 cups per day. You sample 30 adults and find the average is 1.85 cups per day. Test the claim above at the alpha = 0.05 significance level. What do you conclude about the number of cups of coffee that adults consume each day? Group of answer choices - You cannot reject the null hypothesis. Even though your sample indicated 1.85 cups, there still is not sufficient evidence to overturn the claim that adults consume 1.7 cups per day. - This is a borderline case where the test statistic and the critical values are the same. We can neither accept nor reject the null hypothesis in this case. - You reject the null hypothesis. With thirty people consuming 1.85 cups on average , there is sufficient evidence to overturn the claim that adults consume 1.7 cups per day.You wish to test the claim that the average IQ score is less than 100 at the .01 significance level. You determine the hypotheses are: Ho: μ=100 H1:μ<100H You take a simple random sample of 79 individuals and find the mean IQ score is 98.3, with a standard deviation of 15.3. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ score is less…
- A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.2 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim. Hypothesis test results: p: Mean of variable Ho : µ = 2.2 HA: H> 2.2 Variable Sample Mean Length Std. Err. 2.38563 0.251663 499 0.737613 DF T-Stat P-value 0.2305(a) Determine the null and alternative hypotheses that would be used to test the effectiveness of the marketing campaign. Ho: = μ 56 H₁: μ > 56 (Type integers or decimals. Do not round.) (b) A sample of 884 Americans provides enough evidence to conclude that marketing campaign was effective. Provide a statement that should be put out by the marketing department. O A. There is not sufficient evidence to conclude that the mean consumption of popcorn has risen. B. There is sufficient evidence to conclude that the mean consumption of popcorn has risen. C. There is sufficient evidence to conclude that the mean consumption of popcorn has stayed the same. D. There is not sufficient evidence to conclude that the mean consumption of popcorn has stayed the same.Select the most appropriate response. It is claimed that the mean age of bus drivers in Chicago is 59.3 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis? Question 2 options: There is not sufficient evidence to reject the claim µ = 59.3. There is sufficient evidence to reject the claim p = 59.3. There is not sufficient evidence to support the claim p = 59.3. There is sufficient evidence to support the claim u = 59.3.
- You wish to test the claim that the average IQ score is less than 100 at the .10 significance level. You determine the hypotheses are: Ho: μ=100Ho: μ=100 H1:μ<100H1:μ<100 You take a simple random sample of 73 individuals and find the mean IQ score is 95.2, with a standard deviation of 15.1. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ…Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Various temperature measurements are recorded at different times for a particular city. The mean of 20°C is obtained for 60 temperatures on 60 different days. Assuming that Η = 1.5°C, test the claim that the population mean is 22°C. Use a 0.05 significance level.Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…