We want to conduct a hypothesis test of the claim that for middle-aged adults the population mean of their cholesterol levels is less than 195.2mgdLmga random sample of such levels. The sample has a mean of 191.2 and a standard deviation of 20dL-0O It is unclear which test statistic to use.For each of the following sampling scenarios, choose an appropriate test statistic for our hypothesis test on the population mean. Then calculate that statistic.Round your answers to two decimal places.(a) The sample has size 20, and it is from a population with a distribution about which we know very little.оOt=(b) The sample has size 95, and it is from a non-normally distributed population with a known standard deviation of 19.2.O z= 0dLO -0O It is unclear which test statistic to use.We choose

Hypothesized Population mean, Sample mean, Sample standard deviation,

Answered: We want to conduct a hypothesis test of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (Ha) at a significance level of α=0.02α=0.02. Ho:μ=58.8Ho:μ=58.8 Ha:μ>58.8Ha:μ>58.8You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 70.9 41.4 73.5 77.6 63.1 53.9
Jimmy collected a random sample of 30 psychology majors and administered an IQ test. This group had an average IQ of M = 110. Compare this statistic to the general population, which has a mean IQ of 100 and a standard deviation of 15.   Use alpha of .05 and a two tailed test Step 1: Pick the Test: Hypotheses: Step 2: Alpha: One-tail or two-tail: Decision Rule (What is the critical value): Step 3: Calculations Step: 4 Interpretation What did you do? What did you find (include APA)? What does it mean? Did you reject or fail to reject null hypothesis: APA? Step 4:
You wish to test the claim that the average IQ score is less than 100 at the .01 significance level. You determine the hypotheses are: Ho: μ=100 H1:μ<100H You take a simple random sample of 79 individuals and find the mean IQ score is 98.3, with a standard deviation of 15.3. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ score is less…
Need step by step directions to determine the P-value. Thanks
You wish to test the following claim (HaHa) at a significance level of α=0.05 Ho:μ=59.9 Ha:μ>59.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=93n=93 with mean M=62.6M=62.6 and a standard deviation of SD=9.4SD=9.4.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 59.9. The sample data support the claim that the…
You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. Ho:μ=66.4Ho:μ=66.4 Ha:μ>66.4Ha:μ>66.4You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 100.4 87.6 88.2 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 66.4. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 66.4. The sample data support the claim that the…
You wish to test the following claim (HaHa) at a significance level of 0.10.      Ho:μ=80.1Ho:μ=80.1      Ha:μ<80.1Ha:μ<80.1 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=11n=11 with mean M=70.3M=70.3 and a standard deviation of SD=7.7SD=7.7. The test statistic is -4.221 What is the p-value for this sample?
. A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach. Sample mean = 3.12               s = 0.59                       n = 9                α = 0.01 H0: µ = 2.85 H1: µ > 2.85 The test statistics is (Round to three decimal places)
The manufacturer claims that your new car gets 24 mpg on the highway. You suspect that the mpg is less for your car. The 44 trips on the highway that you took averaged 22.3 mpg and the standard deviation for these 44 trips was 4.2 mpg. What can be concluded at the αα = 0.05 level of significance? For this study, we should use (t-test for population mean, z-test for population proportion) The null and alternative hypotheses would be: H0: (symbol) (symbol) ____    H1: (symbol) (symbol) ____    The test statistic (?,t,z) =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is (?, less than or equal to, more than) αα Based on this, we should (accept, reject, fail to reject) the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly less than 24 at αα = 0.05, so there is statistically insignificant evidence to conclude…
You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01. Ho:μ=81.9 Ha:μ≠81.9You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=12n=12 with mean M=72.6M=72.6 and a standard deviation of SD=7.5SD=7.5.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = ______The p-value is... A.) less than (or equal to) αα B.) greater than α This p-value leads to a decision to... A.) reject the null B.) accept the null C.) fail to reject the null As such, the final conclusion is that... A.) There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 81.9. B.) There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 81.9. C.) The sample data support the claim that the population mean is not equal to 81.9. D.) There is not sufficient sample evidence to…
A marketing researcher would like to compare the mean amounts that men and women spend on Christmas gifts. Independent random samples were taken from each group. He would like to conduct a test to determine if women spend more on average. If the null hypothesis is Ho : µM - µf = 0, what is the alternative hypothesis? ge 2: ge 3: OH1 : µM – HF 0 4 OH1 : µM – HF # 0 Page 5: Next Page Dege 10of15
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3,300. A random sample of 12 assisted-living facilities had an average rate of $3,690 per month. The standard deviation for this sample was $530. Medicare would like to set α = 0.02. The critical value for this hypothesis test would be

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