The test statistic of z= 1.79 is obtained when testing the claim that p > 0.9. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.10, should we reject H, or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test. b. P-value= c. Choose the correct conclusion below. (Round to three decimal places as needed.) *** O A. Fail to reject Ho. There is not sufficient evidence to support the claim that p > 0.9. Fail to reject Ho. There is sufficient evidence to support the claim that p > 0.9. O B. O C. Reject Ho. There is sufficient evidence to support the claim that p > 0.9. O D. Reject Ho. There is not sufficient evidence to support the claim that p > 0.9.
The test statistic of z= 1.79 is obtained when testing the claim that p > 0.9. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.10, should we reject H, or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test. b. P-value= c. Choose the correct conclusion below. (Round to three decimal places as needed.) *** O A. Fail to reject Ho. There is not sufficient evidence to support the claim that p > 0.9. Fail to reject Ho. There is sufficient evidence to support the claim that p > 0.9. O B. O C. Reject Ho. There is sufficient evidence to support the claim that p > 0.9. O D. Reject Ho. There is not sufficient evidence to support the claim that p > 0.9.
MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![**Positive z Scores**
This table represents the cumulative area from the left under the standard normal (z) distribution. The cumulative probability is given for positive z-scores, ranging from 0.0 to 3.4. The table facilitates finding the probability associated with a particular z-score in a standard normal distribution.
**Explanation of the Table:**
- **Top and Side Labels:**
- The top row increments by 0.01, representing additional hundredths added to the base z-score from the leftmost column.
- The leftmost column lists z-scores in increments of 0.1 from 0.0 to 3.4.
- **Body of the Table:**
- Each cell contains the cumulative probability up to that z-score. For instance, a z-score of 0.1, with an additional 0.03 (z-score = 0.13), corresponds to a cumulative probability of 0.5517.
**Diagram Above the Table:**
- **Standard Normal Distribution Curve:**
- The diagram at the top shows a bell curve illustrating the standard normal distribution, indicating the symmetry around zero.
**Using the Table:**
1. **Locate the Row:** Find the first decimal place on the z score in the leftmost column.
2. **Locate the Column:** Find the second decimal place across the top row.
3. **Find the Intersection:** The intersection gives the cumulative probability from the left up to that z-score.
This table is crucial for statistical analyses involving the standard normal distribution, allowing users to determine probabilities associated with z-scores and make informed decisions based on probability and statistical inference.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F793c8e2d-e8ae-43e6-85fb-b1622cc5ca2a%2Fe621f07c-3989-4e29-8fb0-dd830af47fb2%2Ff9k68c9_processed.png&w=3840&q=75)
Transcribed Image Text:**Positive z Scores**
This table represents the cumulative area from the left under the standard normal (z) distribution. The cumulative probability is given for positive z-scores, ranging from 0.0 to 3.4. The table facilitates finding the probability associated with a particular z-score in a standard normal distribution.
**Explanation of the Table:**
- **Top and Side Labels:**
- The top row increments by 0.01, representing additional hundredths added to the base z-score from the leftmost column.
- The leftmost column lists z-scores in increments of 0.1 from 0.0 to 3.4.
- **Body of the Table:**
- Each cell contains the cumulative probability up to that z-score. For instance, a z-score of 0.1, with an additional 0.03 (z-score = 0.13), corresponds to a cumulative probability of 0.5517.
**Diagram Above the Table:**
- **Standard Normal Distribution Curve:**
- The diagram at the top shows a bell curve illustrating the standard normal distribution, indicating the symmetry around zero.
**Using the Table:**
1. **Locate the Row:** Find the first decimal place on the z score in the leftmost column.
2. **Locate the Column:** Find the second decimal place across the top row.
3. **Find the Intersection:** The intersection gives the cumulative probability from the left up to that z-score.
This table is crucial for statistical analyses involving the standard normal distribution, allowing users to determine probabilities associated with z-scores and make informed decisions based on probability and statistical inference.
![The test statistic of \( z = 1.79 \) is obtained when testing the claim that \( p > 0.9 \).
a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.
b. Find the P-value.
c. Using a significance level of \( \alpha = 0.10 \), should we reject \( H_0 \), or should we fail to reject \( H_0 \)?
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
---
**Steps:**
**a.** This is a [Dropdown: two-tailed, left-tailed, right-tailed] test.
**b.** P-value = [Text box: (Round to three decimal places as needed.)]
**c.** Choose the correct conclusion below.
- A. Fail to reject \( H_0 \). There is not sufficient evidence to support the claim that \( p > 0.9 \).
- B. Fail to reject \( H_0 \). There is sufficient evidence to support the claim that \( p > 0.9 \).
- C. Reject \( H_0 \). There is sufficient evidence to support the claim that \( p > 0.9 \).
- D. Reject \( H_0 \). There is not sufficient evidence to support the claim that \( p > 0.9 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F793c8e2d-e8ae-43e6-85fb-b1622cc5ca2a%2Fe621f07c-3989-4e29-8fb0-dd830af47fb2%2Frbgt3y9_processed.png&w=3840&q=75)
Transcribed Image Text:The test statistic of \( z = 1.79 \) is obtained when testing the claim that \( p > 0.9 \).
a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.
b. Find the P-value.
c. Using a significance level of \( \alpha = 0.10 \), should we reject \( H_0 \), or should we fail to reject \( H_0 \)?
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
---
**Steps:**
**a.** This is a [Dropdown: two-tailed, left-tailed, right-tailed] test.
**b.** P-value = [Text box: (Round to three decimal places as needed.)]
**c.** Choose the correct conclusion below.
- A. Fail to reject \( H_0 \). There is not sufficient evidence to support the claim that \( p > 0.9 \).
- B. Fail to reject \( H_0 \). There is sufficient evidence to support the claim that \( p > 0.9 \).
- C. Reject \( H_0 \). There is sufficient evidence to support the claim that \( p > 0.9 \).
- D. Reject \( H_0 \). There is not sufficient evidence to support the claim that \( p > 0.9 \).
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