Statémént A single line diagram of a power system is shown in Fig.3.1. All the sequence reactances of the power system components are depicted in per unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line to ground fault occurs on phase a through a reactance of 150 ohm at F, determine the current in ampere fed into the fault. The fault point F is assumed to be at 65% of transmission line length from the bus bar connected to generators A and B. 20 MVA |Xa~X;~ j ®.1 Xy~j 0.35 n 1I KV X;=j0.3 X-j0.3 Xy-j0.05/ 20 MVA X,=j0.25 X;=j0.25 Xy=j0.05 110 KV Transmission X-X,-X-J 0.1 X-X=X¢=j 0.1 circuit D |Xr-Xx= j®.1 Xx=j 0.35 X-X-Xrj 0.1 X-X-X 0.1

Introductory Circuit Analysis (13th Edition)
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Chapter1: Introduction
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Statement
A single line diagram of a power system is shown in Fig.3.1. All the
sequence reactances of the power system components are depicted in per
unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line
to ground fault occurs on phase a through a reactance of 150 ohm at F,
determine the current in ampere fed into the fault. The fault point F is
assumed to be at 65% of transmission line length from the bus bar
connected to generators A and B.
20 MVA
|X-~X;~j ®.1 Xy~j 0.35
II KV
A
X;-j0.3
X;-j0.3
X-j0.05/
110 KV
Transmission
20 MVA
X,-j0.25
X;=j0.25
Xo-j0.05
X-X;=Xy¬J 0.1
X-X,=Xx=j 0.1
circuit
B
D
|Xr-Xx= j®.1 Xx=j 0.35
X-X-X-J 0.1
X-X,~Xg~j 0,1
Transcribed Image Text:Statement A single line diagram of a power system is shown in Fig.3.1. All the sequence reactances of the power system components are depicted in per unit on 20 MVA base, 110KV (L-L) in transmission circuit. If a single line to ground fault occurs on phase a through a reactance of 150 ohm at F, determine the current in ampere fed into the fault. The fault point F is assumed to be at 65% of transmission line length from the bus bar connected to generators A and B. 20 MVA |X-~X;~j ®.1 Xy~j 0.35 II KV A X;-j0.3 X;-j0.3 X-j0.05/ 110 KV Transmission 20 MVA X,-j0.25 X;=j0.25 Xo-j0.05 X-X;=Xy¬J 0.1 X-X,=Xx=j 0.1 circuit B D |Xr-Xx= j®.1 Xx=j 0.35 X-X-X-J 0.1 X-X,~Xg~j 0,1
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