a. Three phase (3ph), phase to phase, and single line to ground (SLG) at 138kV bus. b. 3ph, and SLG at 34.5kV bus. 138/34.5 transformers have the same Z and are in parallel. c. 3ph, and SLG at 34.5kV at 34.5/12.47 substation high side. d. 3ph, and SLG at 12.47kV bus e. 3ph, and SLG at 12.47kV tap f. 3ph, and SLG at 12.47kV end of line (EOL)
Short Transmission Line
A short transmission line is a transmission line that has a length less than 80 kilometers, an operating voltage level of less than 20 kV, and zero capacitance effect.
Power Flow Analysis
Power flow analysis is a topic in power engineering. It is the flow of electric power in a system. The power flow analysis is preliminary used for the various components of Alternating Current (AC) power, such as the voltage, current, real power, reactive power, and voltage angles under given load conditions and is often known as a load flow study or load flow analysis.
Complex Form
A power system is defined as the connection or network of the various components that convert the non-electrical energy into the electric form and supply the electric form of energy from the source to the load. The power system is an important parameter in power engineering and the electrical engineering profession. The powers in the power system are primarily categorized into two types- active power and reactive power.
1) For the utility radial distribution system shown on figure below (only generator is at 138kV). All impedances are in per unit on a 100MVA base and nominal voltage shown. All transformer connected taps equal nominal voltage shown. All breakers and switches are closed unless marked with N.O. (Normally Open). Calculate fault current magnitudes in rms symmetrical amps at the following locations (faults are bolted, one at a time, not simultaneous.)
a. Three phase (3ph), phase to phase, and single line to ground (SLG) at 138kV bus.
b. 3ph, and SLG at 34.5kV bus. 138/34.5 transformers have the same Z and are in parallel.
c. 3ph, and SLG at 34.5kV at 34.5/12.47 substation high side.
d. 3ph, and SLG at 12.47kV bus
e. 3ph, and SLG at 12.47kV tap
f. 3ph, and SLG at 12.47kV end of line (EOL)
g. State the 138kV source (generator) amps for the 3ph at 12.47kV EOL fault.

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