State the null and alternative hypotheses.O Ho: Median time without relaxantMedian time with relaxant >H₂: Median time without relaxant - Median time with relaxant-O Ho: Median time without relaxant - Median time with relaxant #: Median time without relaxant Median time with relaxant =H₂:Ho: Median time without relaxant -Median time with relaxant s: Median time without relaxant Median time with relaxant =H₂:O Ho: Median time without relaxant Median time with relaxant =H₂: : Median time without relaxantMedian time with relaxant =O HoMedian time with relaxant >Ha: Median time without relaxant Median time with relaxant =: Median time without relaxantFind the value of the test statistic.T+=--Need Help?--Find the p-value. (Round your answer to four decimal places.)p-value =What is your conclusion?O Do not reject Ho. There is not sufficient evidence to conclude thatReject Ho. There is not sufficient evidence to conclude that the reReject Ho. There is sufficient evidence to conclude that the relaxaDo not reject Ho. There is sufficient evidence to conclude that the approximately symmetric.A sample of 10 men was used in a study to test the effectswithout the relaxant follow.Subject12345678910RelaxantNo Yes16 1113 923810681014813109596125Use a 0.05 level of significance to determine whether the reState the null and alternative hypotheses.O Ho: Median time without relaxant Median time with re

Given data: Subject Yes No 1 16 11 2 13 9 3 23 13 4 8 10 5 10 9 6 6 5 7 8 9 8 10…

Answered: State the O Ho: Median time without…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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DO MALES AND FEMALES DIFFER ON ATTITUDES TOWARD CRIME ? MALES N=12 FEMALES N=13 CRIME ATTITUDE MALES 77, 97, 28, 55, 75, 43, 21, 70, 91, 22, 58, 45 FEMALES 32,31, 89, 21, 79, 67, 41, 24, 43, 87, 64, 28, 21 MEAN SD MALE FEMALE • DV= 1 •T-VALUE • df • SIGNIFICANT (Y/N). • TEST STATISTIC RAN • ACCEPT OR REJECT NULL HYPOTHESIS. • CONCLUSION:
Calculate the p value State the conclusion
Test the claim that for the population of statistics final exams, the mean score is 7676 using alternative hypothesis that the mean score is different from 76.76. Sample statistics include ?=21,n=21, ?⎯⎯⎯=78,x¯=78, and ?=11.s=11. Use a significance level of ?=0.05.α=0.05. (Assume normally distributed population.) The test statistic is The positive critical value is The negative critical value is The conclusion is A. There is sufficient evidence to reject the claim that the mean score is equal to 76. B. There is not sufficient evidence to reject the claim that the mean score is equal to 76.
Testing:H0:U=9.27H1:U>9.27Your sample consists of 23 subjects, with a mean of 11.6 and standard deviation of 4.86.Calculate the test statistic, rounded to 2 decimal places. t=
What is the value of the test statistic? Find the p-value What is the appropriate conclusion at α=0.10? do not round please
For each of the following hypotheses in Questions 6-8, (i) provide the p-value (or its bounds) and (ii) draw a basic conclusion (REJECT or DO NOT REJECT only) with respect to Ho with 99% confidence. Handwritten notes are not necessary for these questions.
K L M
In a test, the average score is 100. You believe that the average score for your class is higher. You took a sample of 30 students. The average score for this group is 140 with a standard deviation of 15. Test the hypothesis that the average score is greater. Use a = The rejection region for the test statistic is... .05. less than -1.959963985 and greater than 1.959963985 less than - 2.045229642 and greater than 2.045229642 less than - 1.644853627 and greater than 1.644853627 none of the above O O O O
The results obtained from statistics analysis between the pulse rate at baseline and the pulse rate after smoking using t-test is 0.001, what should be the decision? reject the null hypothesis do not reject the null hypothesis restate the null hypothesis no decision
Application Exercise: Dr. Butler is interested in the preference for dog breeds among college students. She collected the observed frequencies below and wants to know if the breeds are equally preferred. What can be concluded with an a of 0.05? Irish Setter Golden Retriever Papillon Great Dane 101 94 135 97 L What is the appropriate test statistic? -Select Compute the statistic selected in : M Obtain/compute the appropriate values to make a decision about Hg. Critical Value = | J: Test Statistic = Decision: -Select- N Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. Effect Size = | ]: Magnitude: -Select-- Make an interpretation based on the results. O There is a significant relationship between dog breeds and college students. There is a significant dog breed preference among college students. O Dog breeds are equally preferred among college students.
I need help only with the lat part of the exercise
typed please

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