Test the claim that for the population of statistics final exams, the mean score is 7676 using alternative hypothesis that the mean score is different from 76.76. Sample statistics include ?=21,n=21, ?⎯⎯⎯=78,x¯=78, and ?=11.s=11. Use a significance level of ?=0.05.α=0.05. (Assume normally distributed population.) The test statistic is The positive critical value is The negative critical value is The conclusion is A. There is sufficient evidence to reject the claim that the mean score is equal to 76. B. There is not sufficient evidence to reject the claim that the mean score is equal to 76.
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Test the claim that for the population of statistics final exams, the
The test statistic is
The positive critical value is
The negative critical value is
The conclusion is
A. There is sufficient evidence to reject the claim that the mean score is equal to 76.
B. There is not sufficient evidence to reject the claim that the mean score is equal to 76.
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- Can you tell me what the solution would be to this one?Total blood volume (in ml) per body weight (in kg) is important in medical research. For healthy adults, the red blood cell volume mean is about µ = 28 ml/kg with a standard deviation of 4.75ml/kg. Red blood cells volume that is too low or too high can indicate a medical problem. Suppose he does a hypothesis test with a significance level of 0.01. Roger has had seven blood tests and the red blood cell volumes were: 32 25 41 35 30 37 29 Roger’s null hypothesis is that his blood tests are normal and that his alternative hypothesis is that something is wrong. Symbolically, the null and hypotheses are as follows Ho: µ = 28 ml/kg and Hi: µ ≠ 28 ml/kg What value of the test statistic (z) should he report? (Sampling a Normal Distribution for the Mean µ) Group of answer choices a. 0.99 b.2.42 c.2.62 d.2.22This research was conducted with Korean adolescents in the Los Angeles area. Would you be willing to generalize the results of this study to Korean adolescents who live in other regions of the country? Why or why not.
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O a z=186; P-value = 0.0314; reject null hypothesis O b. z 186, P-value = 0.0628; reject null hypothesis O c. z=0.36; P-value = 0.7188, do not reject null hypothesis Od. z=0.36, P-value = 0.3594; do not reject null hypothesisDo men talk less than women? The table shows results from a study of the words spoken in a day by men and women. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. At the 0.05 significance level, test the claim that the mean number of words spoken by men is less than the mean number of words spoken by women. Men Women n1 = 212 n2 = 218 xˉx̄1 = 15706.4 words xˉx̄2 = 15683.2 words s1 = 1595.44 words s2 = 1597.54 words What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer μ₁ μ σ₁² x̄₂ p x̄₁ s₁² p̂₁ μ(men) p₂ p₁ μ₂ ? ≤ > ≥ = ≠ < Select an answer μ₁ p₁ μ₂ x̄₂ σ₁² p̂₁ μ s₁² μ(women) p x̄₁ p₂ H1: Select an answer p̂₂ p s₂² σ₂² μ(men) μ μ₂ x̄₂ x̄₁ p₂ μ₁ p₁ ? < > = ≠ ≥ ≤ Select an answer μ₂ μ p₂ s₁² p₁ x̄₁ σ₁² p̂₁ p μ₁ x̄₂ μ(women) Original Claim = Select an answer H₁ H₀ df = Based on the hypotheses, find the…PLEASE ONLY SELECT THE ANSWERS AS SHOWN FOR THE MULTIPLE CHOICE, SUCH AS OPTION 1, 2, ETC. 1) In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.8 and a standard deviation of 1.51. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. H0: μ=0 mg/dL H1: μ<0 mg/dL B. H0: μ>0 mg/dL H1: μ<0 mg/dL C. H0: μ=0 mg/dL H1: μ≠0 mg/dL D. H0: μ=0 mg/dL H1: μ>0 mg/dL…You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly more than 0.52. You use a significance level of a = 0.05. Ho:p = 0.52 H1:p> 0.52 You obtain a sample of size n = 556 in which there are 308 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that. There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.52. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more…Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. 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Standard deviationA researcher wants to measure average cardiovascular health of university students and compare those scores to the average scores in the general population. Assuming that population variance is known, what statistical test is most appropriate for this study? independent-samples t-test single-sample t-test z-test for sample mean related-samples t-testData on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 26 26 0.79911 Ib 0.81326 Ib S 0.00445 Ib 0.00759 Ib ..... a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. 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