lick the icon to view the TI-83/84 Plus calculator results. Calculator results s the conclusion for this hypothesis test? One-way ANOVA F= 2.2487822823 p=0.1209974555 Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. Reject Ho. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score Factor Reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. df = 2 SS = 336.996362 | MS = 168.498181 Fail to reject Hg. There is insufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. One-way ANOVA t MS = 168.498181 Erron df = 34 SS = 2547.57350 MS = 74.9286323 Sxp = 8.65613264 Print Done

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading
Ease score.
A Click the icon to view the TI-83/84 Plus calculator results.
Calculator results
What is the conclusion for this hypothesis test?
One-way ANOVA
F= 2.2487822823
O A. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score.
O B. Reject Hn. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score.
p= 0.1209974555
Factor
O C. Reject Hn. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score.
df = 2
O D. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score.
SS = 336.996362
Į MS = 168.498181
One-way ANOVA
↑ MS = 168.498181
Error
df = 34
SS = 2547.57350
MS = 74.9286323
Sxp = 8.65613264
Print
Done
Transcribed Image Text:Samples of pages were randomly selected from three different novels. The Flesch Reading Ease scores were obtained from each page, and the TI-83/84 Plus calculator results from analysis of variance are given below. Use a 0.05 significance level to test the claim that the three books have the same mean Flesch Reading Ease score. A Click the icon to view the TI-83/84 Plus calculator results. Calculator results What is the conclusion for this hypothesis test? One-way ANOVA F= 2.2487822823 O A. Fail to reject Ho. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. O B. Reject Hn. There is insufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. p= 0.1209974555 Factor O C. Reject Hn. There is sufficient evidence to warrant the rejection of the claim that the three books have the same mean Flesch Reading Ease score. df = 2 O D. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the three books have the same mean Flesch Reading Ease score. SS = 336.996362 Į MS = 168.498181 One-way ANOVA ↑ MS = 168.498181 Error df = 34 SS = 2547.57350 MS = 74.9286323 Sxp = 8.65613264 Print Done
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