For each of the following hypotheses in Questions 6-8, (i) provide the p-value (or its bounds) and (ii) draw a basic conclusion (REJECT or DO NOT REJECT only) with respect to Ho with 99% confidence. Handwritten notes are not necessary for these questions.
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- (a) State the null and alternative hypotheses. Which of the following is correct? O A. Ho: H1 = H2; Hai H1 #H2 O B. Ho: H1 = H2; Hai H1 > H2 OC. Ho: H1 = H2; HaiH1In a recent Super Bowl, a TV network predicted that 49 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 98 people who saw the commercials and found that 50 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.49 Ha:p > 0.49 Calculate the test statistic, rounded to 3 decimal places 2In a recent Super Bowl, a TV network predicted that 33 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 146 people who saw the commercials and found that 45 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.33 Ha:p + 0.33 (a) Calculate the sample test statistic: (b) Calculate the standardarized test statistic (the z-score). Z =Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 375 millionaires surveyed, 34 could wiggle their ears. What can be concluded at the αα = 0.10 level of significance? The null and alternative hypotheses would be: H0:? μ p Select an answer < ≠ > = (please enter a decimal) H1: ? μ p Select an answer > < = ≠ (Please enter a decimal) The test statistic? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.)Questions 1 and 2: Set up the Null and Alternative hypotheses to test the following claims: 1. A health insurance company wants to determine if more than 25% of U.S. residents have been to a hospital emergency room within the past year. State the null and alternative hypotheses. H0: HA: 2. A company makes canned clam chowder (a delicious New England tradition). On the label, the company claims that the chowder contains (on average) 3.5 grams of Total Fat per serving. A consumer group would like to test this claim is true. State the null and alternative hypotheses that you would use to test if the mean amount of Total Fat per serving differs from 3.5 grams: H0: HA:Questions 1 and 2: Set up the Null and Alternative hypotheses to test the following claims: 1. A health insurance company wants to determine if less than 25% of U.S. residents have been to a hospital emergency room within the past year. State the null and alternative hypotheses. H0: HA: 2. A company makes canned clam chowder (a delicious New England tradition). On the label, the company claims that the chowder contains (on average) 3.5 grams of Total Fat per serving. A consumer group would like to test this claim is true. State the null and alternative hypotheses that you would use to test if the mean amount of Total Fat per serving differs from 3.5 grams: H0: HA:10% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 302 people from the inner city surveyed, 36 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 10% at αα = 0.05, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 10%. The data suggest the population proportion is not…For each of the following hypotheses, identify which statistical test we could run in order to address the specific research question being asked. Your options are: z-Test, One-Sample t-Test, Independent-Samples t-Test, and Paired-Samples t-Test. Be sure to mention a bit about the research design to explain why you chose that specific test: 1) Do the Dodgers and Giants differ in the number of strikeouts they have per game? 2) Does our stats class differ from the national average in IQ? 3) Do people perform better or worse on a cognitive task after they eat cookies? 4) Do "only children" drive safer than other children with siblings? 5) Do people have more friends in college than they did in high school? 6) Do people experience higher levels of sadness or anger after a specific negative outcome?Normally only about 19% of people who try to quit smoking succeed, but sellers of a motivational tape claim that listening to their recorded messages can help people quit (i.e., more than 19% of the people who use the tapes will successfully quit). Let p represents the percentage of people who have listened to the recorded messages and have successfully quit. Match the appropriate null and alternative hypotheses, based on the sellers' claim. H,: p = 0.19 p> 0.19 p2 0.19 ps 0.19 p 0.19 p2 0.19 ps 0.19 p < 0.19 Op- 0.19 Do you consider a Type I or Type Il error a more serious mistake here? Why? Your answer should make it clear what Type I and Il errors are in this context.In a recent Super Bowl, a TV network predicted that 56 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 85 people who saw the commercials and found that 47 of them said they would watch one of the television shows. Suppose you are have the following null and alternative hypotheses for a test you are running: Ho:p = 0.56 Ha:p0.56 Calculate the test statistic, rounded to 3 decimal places 2 =19% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 338 randomly selected students who receive financial aid, 44 of them volunteered their time. What can be concluded at the α = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: (please enter a decimal) Please enter a decimal) c. The test statistic (please show your answer to 3 decimal places.) 2 (Please show your answer to 4 decimal places.) d. The p-value e. The p-value is? a f Based on this, we should Select an answer g. Thus, the final conclusion is that the null hypothesis. The data suggest the population proportion is not significantly lower than 19% at α-0.05, so there is insufficient evidence to conclude that the percentage of financial aid recipients who volunteer is lower than 1996. The data suggest the population proportion is not significantly…16% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 396 people from the inner city surveyed, 59 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 16% at αα = 0.05, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is smaller than 16%. The data suggest the population proportion…SEE MORE QUESTIONS
