13% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those wholive in the inner city have sleep apnea. Of the 390 people from the inner city surveyed, 70 of them sufferedfrom sleep apnea. What can be concluded at the level of significance of a = 0.10?b. The null and alternative hypotheses would be:Ho:Select an answer(please enter a decimal)H1: ? 0Select an answer O(Please enter a decimal)C. The test statistic(please show your answer to 3 decimal places.)d. The p-value =(Please show your answer to 4 decimal places.)e. The p-value is? O af. Based on this, we shouldSelect an answer the null hypothesis.

Given data number of success , x= 70 sample size, n =390 population proportion,p=…

Answered: 13% of all Americans suffer from sleep…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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When we test the hypothesis that the population proportions are equal, we can use the Z test for a one-sided as well as a two-sided alternative. Select one: a. False b. True C. Not sure
In a memory test, the test subjects are given a large number and are asked to memorize it. Historical records show that 80% of test subjects pass the test. To pass the test, a subject must exactly repeat all the digits in the number after two hours. A random sample of 625 people to take the memory test is going to be chosen. Let p be the proportion of people in the sample who pass the test. Answer the following. (If necessary, consult a list of formulas.) (a) Find the mean of P. 0 (b) Find the standard deviation of p. 0 (c) Compute an approximation for P(P >0.84), which is the probability that more than 84% of the people in the sample pass the test. Round your answer to four decimal places. 0 X
According to a report on consumer fraud and identity theft, 24% of all complaints for a year were for identity theft. In that year, Connecticut had 861 complaints of identity theft out of 3484 consumer complaints. Does this data provide enough evidence to show that Connecticut had a higher proportion of identity theft than 24% ? Test at the 10% level. State the hypotheses. Ho: P? O Ha: P ? Calculate the test statistic. Round to four decimal places. p = Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is greater than .10, reject Ho. O Since the p-value is less than .10, fail to reject Ho- O Since the p-value is greater than .10, fail to reject Ho. O Since the p-value is less than .10, reject Ho. Interpret the results. O At the 10% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Connecticut is…
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In an article that appears on a website,† Carlton Gunn, a public defender in Seattle, Washington, wrote about how he uses statistics in his work as an attorney. He states the following. I personally have used statistics in trying to challenge the reliability of drug testing results. Suppose the chance of a mistake in the taking and processing of a urine sample for a drug test is just 1 in 100. And your client has a "dirty" (i.e., positive) test result. Only a 1 in 100 chance that it could be wrong? Not necessarily. If the vast majority of all tests given—say 99 in 100—are truly clean, then you get one false dirty and one true dirty in every 100 tests, so that half of the dirty tests are false. Define the following events as given below. TD = event that the test result is dirty TC = event that the test result is clean D = event that the person tested is actually dirty C = event that the person tested is actually clean (a) Using the information in the quote, compute the following…
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A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned. Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.” Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations. 1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.
The National Longitudinal Study of Adolescent Health interviewed a random sample of 4877 teens (grades 7 to 12). One question asked, “What do you think are the chances you will be married in the next 10 years?” Given is a two-way table of the responses by gender. Which of the following is the appropriate null hypothesis for performing a chi-square test?
Solve for the p-value.
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You create three versions of a survey, each with different ways of phrasing the questions (positive, negative, or neutral). You randomly assign participants to one of the three surveys, each of which has 20 items for which participants rate their agreement. After collecting the surveys, you calculate an average agreement score for each participant. If testing hypotheses about question phrasing on agreement, it would be most appropriate to calculate a. 1) O One-way (independent) ANOVA ›2)Repeated measures ANOVA 3) factorial ANOVA Factorial ANOVA

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