State the null and alternative hypotheses. O Ho: Not all the population means are equal. Ha: MA MB MC OHO: MAHB HC Ha: MAHB = MC Ho: MAHB = MC Ha HAMBHC O Ho: At least two of the population means are equal. Ha: At least two of the population means are different. Ho: MAHB = MC Ha: Not all the population means are equal. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is sufficient evidence to conclude that the means of the three treatments are not equal. Reject Ho. There is sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
State the null and alternative hypotheses. O Ho: Not all the population means are equal. Ha: MA MB MC OHO: MAHB HC Ha: MAHB = MC Ho: MAHB = MC Ha HAMBHC O Ho: At least two of the population means are equal. Ha: At least two of the population means are different. Ho: MAHB = MC Ha: Not all the population means are equal. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. O Reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is sufficient evidence to conclude that the means of the three treatments are not equal. Reject Ho. There is sufficient evidence to conclude that the means of the three treatments are not equal. O Do not reject Ho. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
MATLAB: An Introduction with Applications
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Author:Amos Gilat
Publisher:Amos Gilat
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
Transcribed Image Text:## Analysis of Variance for Completely Randomized Design
The table below presents data for an analysis of variance (ANOVA) to determine if there is a significant difference between the means of three treatments: A, B, and C. The level of significance is set at α = 0.05.
### Data Table
| Treatment | | |
|-----------|------|------|
| **A** | **B** | **C** |
| 135 | 107 | 91 |
| 119 | 114 | 83 |
| 114 | 124 | 86 |
| 106 | 104 | 101 |
| 132 | 108 | 89 |
| 115 | 110 | 116 |
| 129 | 96 | 109 |
| 94 | 113 | 119 |
| | 103 | 98 |
| | 81 | 98 |
### Treatment Means
- \( \bar{x}_A = 118 \)
- \( \bar{x}_B = 106 \)
- \( \bar{x}_C = 99 \)
### Treatment Variances
- \( s_A^2 = 193.14 \)
- \( s_B^2 = 132.89 \)
- \( s_C^2 = 153.78 \)
This data will be used to conduct an ANOVA test to determine if there are statistically significant differences between the treatment means.
![**State the Null and Alternative Hypotheses**
- \( H_0 \): Not all the population means are equal.
\( H_a \): \(\mu_A = \mu_B = \mu_C\)
- \( H_0 \): \(\mu_A \neq \mu_B \neq \mu_C\)
\( H_a \): \(\mu_A = \mu_B = \mu_C\)
- \( H_0 \): \(\mu_A = \mu_B = \mu_C\)
\( H_a \): \(\mu_A \neq \mu_B \neq \mu_C\)
- \( H_0 \): At least two of the population means are equal.
\( H_a \): At least two of the population means are different.
- \( H_0 \): \(\mu_A = \mu_B = \mu_C\)
\( H_a \): Not all the population means are equal.
**Find the Value of the Test Statistic**
(Round your answer to two decimal places.)
\[ \boxed{} \]
**Find the \( p \)-value**
(Round your answer to four decimal places.)
\[ p\text{-value} = \boxed{} \]
**State your Conclusion**
- \( \circ \) Reject \( H_0 \). There is not sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Do not reject \( H_0 \). There is sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Reject \( H_0 \). There is sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Do not reject \( H_0 \). There is not sufficient evidence to conclude that the means of the three treatments are not equal.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ad87420-52d2-4e34-815e-eb9bcb5c95c0%2Fb07f2d2c-8f5e-4a39-8dea-fc45b3a370c1%2Foczvoj_processed.png&w=3840&q=75)
Transcribed Image Text:**State the Null and Alternative Hypotheses**
- \( H_0 \): Not all the population means are equal.
\( H_a \): \(\mu_A = \mu_B = \mu_C\)
- \( H_0 \): \(\mu_A \neq \mu_B \neq \mu_C\)
\( H_a \): \(\mu_A = \mu_B = \mu_C\)
- \( H_0 \): \(\mu_A = \mu_B = \mu_C\)
\( H_a \): \(\mu_A \neq \mu_B \neq \mu_C\)
- \( H_0 \): At least two of the population means are equal.
\( H_a \): At least two of the population means are different.
- \( H_0 \): \(\mu_A = \mu_B = \mu_C\)
\( H_a \): Not all the population means are equal.
**Find the Value of the Test Statistic**
(Round your answer to two decimal places.)
\[ \boxed{} \]
**Find the \( p \)-value**
(Round your answer to four decimal places.)
\[ p\text{-value} = \boxed{} \]
**State your Conclusion**
- \( \circ \) Reject \( H_0 \). There is not sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Do not reject \( H_0 \). There is sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Reject \( H_0 \). There is sufficient evidence to conclude that the means of the three treatments are not equal.
- \( \circ \) Do not reject \( H_0 \). There is not sufficient evidence to conclude that the means of the three treatments are not equal.
Expert Solution
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Step 1
The data shows the three treatments mean and variances.
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