bookstore costs $ 96.54. You want to test this claim, The null and alternative hypothesis in symbols would be: O Ho:µ 2 96.54 H1:µ < 96.54 O Ho: µ < 96.54 H1: µ > 96.54 O Ho:p = 96.54 H1:p + 96.54 O Ho:p < 96.54 H:p > 96.54 O Ho:u = 96.54 H1:p + 96.54 O Ho:p 2 96.54 H1:p < 96.54 The null hypothesis in words would be: O The average price of all textbooks from the store is $ 96.54 O The proportion of all textbooks from the store that are less than 96.54 is equal to 50% O The average price of textbooks in a sample is $ 96.54 O The average of price of all textbooks from the store is greater than $ 96.54. O The average of price of all textbooks from the store is less than $ 96.54. Based on a sample of 80 textbooks at the store, you find an average of 110.14 and a standard deviation of 12,8. The point estimate is: (to 3 decimals) The 90 % confidence interval (use z*) is: to (to 3 decimals) Based on this we

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bookstore costs $ 96.54. You want to test this claim.
The null and alternative hypothesis in symbols would be:
O Ho:u 2 96.54
H1: µ < 96.54
O Ho: µ < 96.54
H1:µ > 96.54
O Ho:p = 96.54
H1:p + 96.54
O Ho:p < 96.54
H1:p > 96.54
O Ho:u = 96.54
H1:µ + 96.54
O Ho:p > 96.54
H1:p < 96.54
The null hypothesis in words would be:
O The average price of all textbooks from the store is $ 96.54
O The proportion of all textbooks from the store that are less than 96.54 is equal to 50%
O The average price of textbooks in a sample is $ 96.54
O The average of price of all textbooks from the store is greater than $ 96.54.
O The average of price of all textbooks from the store is less than $ 96.54.
Based on a sample of 80 textbooks at the store, you find an average of 110.14 and a standard
deviation of 12.8.
The point estimate is:
(to 3 decimals)
(to 3 decimals)
The 90 % confidence interval (use z*) is:
to
Rased on this we
Transcribed Image Text:bookstore costs $ 96.54. You want to test this claim. The null and alternative hypothesis in symbols would be: O Ho:u 2 96.54 H1: µ < 96.54 O Ho: µ < 96.54 H1:µ > 96.54 O Ho:p = 96.54 H1:p + 96.54 O Ho:p < 96.54 H1:p > 96.54 O Ho:u = 96.54 H1:µ + 96.54 O Ho:p > 96.54 H1:p < 96.54 The null hypothesis in words would be: O The average price of all textbooks from the store is $ 96.54 O The proportion of all textbooks from the store that are less than 96.54 is equal to 50% O The average price of textbooks in a sample is $ 96.54 O The average of price of all textbooks from the store is greater than $ 96.54. O The average of price of all textbooks from the store is less than $ 96.54. Based on a sample of 80 textbooks at the store, you find an average of 110.14 and a standard deviation of 12.8. The point estimate is: (to 3 decimals) (to 3 decimals) The 90 % confidence interval (use z*) is: to Rased on this we
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