Starting with a stock solution of glucose with a molarity of 0.750 M, four solutions are prepared by serial dilution. At each stage 10.0 mL of solution is diluted to 150.0 mL. The solutions are labeled 1 (stock solution), 2 (first diluted solution), 3 (second diluted solution) and 4 (final solution). Which of the following options correctly describe the solutions prepared? A. Solution 2 contains 7.50 x 10-3 moles of solute. B. The molarity of solution 2 is 7.50 x 10-2 M. C. Solution 4 has a molarity of 2.22 x 10-4 M. D. There are 3.33 x 10-5 moles of solute in solution 4. E. Solution 3 has a molarity of 5.00 x 10-2 M.
Starting with a stock solution of glucose with a molarity of 0.750 M, four solutions are prepared by serial dilution. At each stage 10.0 mL of solution is diluted to 150.0 mL. The solutions are labeled 1 (stock solution), 2 (first diluted solution), 3 (second diluted solution) and 4 (final solution). Which of the following options correctly describe the solutions prepared? A. Solution 2 contains 7.50 x 10-3 moles of solute. B. The molarity of solution 2 is 7.50 x 10-2 M. C. Solution 4 has a molarity of 2.22 x 10-4 M. D. There are 3.33 x 10-5 moles of solute in solution 4. E. Solution 3 has a molarity of 5.00 x 10-2 M.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Starting with a stock solution of glucose with a molarity of 0.750 M, four solutions are prepared by serial dilution. At each stage 10.0 mL of solution is diluted to 150.0 mL. The solutions are labeled 1 (stock solution), 2 (first diluted solution), 3 (second diluted solution) and 4 (final solution). Which of the following options correctly describe the solutions prepared?
A. Solution 2 contains 7.50 x 10-3 moles of solute.
B. The molarity of solution 2 is 7.50 x 10-2 M.
C. Solution 4 has a molarity of 2.22 x 10-4 M.
D. There are 3.33 x 10-5 moles of solute in solution 4.
E. Solution 3 has a molarity of 5.00 x 10-2 M.
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