**Problem 8: Concentration Calculation** **Objective:** Calculate the final concentration of a sodium hydroxide (NaOH) solution. **Given Information:** - Initial volume of NaOH solution: 16.66 mL - Initial concentration of NaOH solution: 6.00 M - Final volume after dilution: 1.00 L **Approach:** To find the final concentration after dilution, use the dilution formula: \[ C_1V_1 = C_2V_2 \] where: - \( C_1 \) is the initial concentration (6.00 M) - \( V_1 \) is the initial volume (16.66 mL) - \( C_2 \) is the final concentration - \( V_2 \) is the final volume (1.00 L or 1000 mL) **Calculation:** 1. Convert initial volume \( V_1 \) to liters, if necessary: \[ V_1 = 16.66 \, \text{mL} = 0.01666 \, \text{L} \] 2. Substitute values into the equation: \[ (6.00\, \text{M}) \times (0.01666\, \text{L}) = C_2 \times (1.00\, \text{L}) \] 3. Solve for \( C_2 \): \[ C_2 = \frac{6.00 \times 0.01666}{1.00} \] 4. Calculate \( C_2 \): \[ C_2 = 0.09996 \, \text{M} \] **Conclusion:** The final concentration of the NaOH solution is approximately **0.10 M** after dilution to 1.00 L.

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**Problem 8: Concentration Calculation**

**Objective:**  
Calculate the final concentration of a sodium hydroxide (NaOH) solution.

**Given Information:**  
- Initial volume of NaOH solution: 16.66 mL
- Initial concentration of NaOH solution: 6.00 M
- Final volume after dilution: 1.00 L

**Approach:**  

To find the final concentration after dilution, use the dilution formula:  
\[ C_1V_1 = C_2V_2 \]  
where:  
- \( C_1 \) is the initial concentration (6.00 M)  
- \( V_1 \) is the initial volume (16.66 mL)  
- \( C_2 \) is the final concentration  
- \( V_2 \) is the final volume (1.00 L or 1000 mL)  

**Calculation:**  
1. Convert initial volume \( V_1 \) to liters, if necessary:  
   \[ V_1 = 16.66 \, \text{mL} = 0.01666 \, \text{L} \]

2. Substitute values into the equation:  
   \[ (6.00\, \text{M}) \times (0.01666\, \text{L}) = C_2 \times (1.00\, \text{L}) \]

3. Solve for \( C_2 \):  
   \[ C_2 = \frac{6.00 \times 0.01666}{1.00} \]

4. Calculate \( C_2 \):  
   \[ C_2 = 0.09996 \, \text{M} \]

**Conclusion:**  
The final concentration of the NaOH solution is approximately **0.10 M** after dilution to 1.00 L.
Transcribed Image Text:**Problem 8: Concentration Calculation** **Objective:** Calculate the final concentration of a sodium hydroxide (NaOH) solution. **Given Information:** - Initial volume of NaOH solution: 16.66 mL - Initial concentration of NaOH solution: 6.00 M - Final volume after dilution: 1.00 L **Approach:** To find the final concentration after dilution, use the dilution formula: \[ C_1V_1 = C_2V_2 \] where: - \( C_1 \) is the initial concentration (6.00 M) - \( V_1 \) is the initial volume (16.66 mL) - \( C_2 \) is the final concentration - \( V_2 \) is the final volume (1.00 L or 1000 mL) **Calculation:** 1. Convert initial volume \( V_1 \) to liters, if necessary: \[ V_1 = 16.66 \, \text{mL} = 0.01666 \, \text{L} \] 2. Substitute values into the equation: \[ (6.00\, \text{M}) \times (0.01666\, \text{L}) = C_2 \times (1.00\, \text{L}) \] 3. Solve for \( C_2 \): \[ C_2 = \frac{6.00 \times 0.01666}{1.00} \] 4. Calculate \( C_2 \): \[ C_2 = 0.09996 \, \text{M} \] **Conclusion:** The final concentration of the NaOH solution is approximately **0.10 M** after dilution to 1.00 L.
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