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Calculate the molarity of a solution of 579.6 g ZNSO4 (molar mass 161.47 g/mol) in 6.5x10“ mL of solution. O A. 8.9x10-3 M O B. 2.5 M O C. none of these O D. 2.5x10-3 M O E. 5,5x10-2 M O F. 18 M O G. 8.9 M O H. 5.5x10-5 M

Calculate the molarity of a solution of 579.6 g ZNSO4 (molar mass 161.47 g/mol) in 6.5x10“ mL of solution. O A. 8.9x10-3 M O B. 2.5 M O C. none of these O D. 2.5x10-3 M O E. 5,5x10-2 M O F. 18 M O G. 8.9 M O H. 5.5x10-5 M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Metric Prefixes and Calculation of Molarity** **Metric Prefixes:** - **centi (c):** \(10^2\) or 100 - **milli (m):** \(10^3\) or 1,000 - **micro (µ):** \(10^6\) or 1,000,000 - **nano (n):** \(10^9\) or 1,000,000,000 --- **Problem:** Calculate the molarity of a solution of 579.6 g ZnSO₄ (molar mass 161.47 g/mol) in \(6.5 \times 10^4\) mL of solution. **Options:** - A. \(8.9 \times 10^{-3}\) M - B. 2.5 M - C. none of these - D. \(2.5 \times 10^{-3}\) M - E. \(5.5 \times 10^{-2}\) M - F. 18 M - G. 8.9 M - H. \(5.5 \times 10^{-5}\) M --- To solve this problem, start by converting the mass of ZnSO₄ into moles using the molar mass, and then calculate the molarity by dividing the moles by the volume of the solution in liters.
Transcribed Image Text:**Metric Prefixes and Calculation of Molarity** **Metric Prefixes:** - **centi (c):** \(10^2\) or 100 - **milli (m):** \(10^3\) or 1,000 - **micro (µ):** \(10^6\) or 1,000,000 - **nano (n):** \(10^9\) or 1,000,000,000 --- **Problem:** Calculate the molarity of a solution of 579.6 g ZnSO₄ (molar mass 161.47 g/mol) in \(6.5 \times 10^4\) mL of solution. **Options:** - A. \(8.9 \times 10^{-3}\) M - B. 2.5 M - C. none of these - D. \(2.5 \times 10^{-3}\) M - E. \(5.5 \times 10^{-2}\) M - F. 18 M - G. 8.9 M - H. \(5.5 \times 10^{-5}\) M --- To solve this problem, start by converting the mass of ZnSO₄ into moles using the molar mass, and then calculate the molarity by dividing the moles by the volume of the solution in liters.
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