measured by molarity (M), which is the number of moles per liter of solution (moles/L). For example,1 M = 1 mole/L. To determine how many grams of a substance is equal to one mole the molecularmass is needed (we will not explore this in this lab rather this is taught in your Chemistry subjects).The general formula for making a dilution solution is the following:CaV1 = C2V2whereC1 = the original concentration of stock solutionVi = the volume of stock solution needed to make working solutionC2 = the desired concentration of working solutionV2 = the desired final volume of working solutionHow would you make a 100 ul working stock at a concentration of 0.5 uM from a stock solutionat a concentration of 0.1 mM? Always remember to put everything into the same units first!For Educational Purposes OnlySLSU-TO/NCMatondoWhat would be the working stock concentration (in molarity) if you diluted 250 µl of a stockconcentration of 10 uM in a total volume of 1 ml?LAB EXERCISE NO. 4. PATTERN OF INHERITANCEn (] II

Note : Since you have posted multiple questions, we are entitled to answer the first only. Please…

V2 = the desired final volume of working solution How would you make a 100 ul working stock at a concentration of 0.5 uM from a stock solution at a concentration of 0.1 mM? Always remember to put everything into the same units first!

V2 = the desired final volume of working solution How would you make a 100 ul working stock at a concentration of 0.5 uM from a stock solution at a concentration of 0.1 mM? Always remember to put everything into the same units first!

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Precipitation Titration

Precipitation analysis is used to analyze drugs, and to measure the salt content in food and beverages. It is an important concept from the examination point of view many practical questions are asked on the topic. This topic is significant in the professional exams for both undergraduate and graduate courses, especially for

Question

measured by molarity (M), which is the number of moles per liter of solution (moles/L). For example,
1 M = 1 mole/L. To determine how many grams of a substance is equal to one mole the molecular
mass is needed (we will not explore this in this lab rather this is taught in your Chemistry subjects).
The general formula for making a dilution solution is the following:
CaV1 = C2V2
where
C1 = the original concentration of stock solution
Vi = the volume of stock solution needed to make working solution
C2 = the desired concentration of working solution
V2 = the desired final volume of working solution
How would you make a 100 ul working stock at a concentration of 0.5 uM from a stock solution
at a concentration of 0.1 mM? Always remember to put everything into the same units first!
For Educational Purposes Only
SLSU-TO/NCMatondo
What would be the working stock concentration (in molarity) if you diluted 250 µl of a stock
concentration of 10 uM in a total volume of 1 ml?
LAB EXERCISE NO. 4. PATTERN OF INHERITANCE
n (] II

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