段階的に解決し、人工知能を使用せず、優れた仕事を行いますご支援ありがとうございましたSOLVE STEP BY STEP IN DIGITAL FORMAT15. In a two-disc coupling the diameters are 480cm and 30cm.Calculate the engine torque transmitted for a contact pressure of 500Kg where the adhesion coefficient is 0.40.16. In a single disc coupling the external and internal diameters are180 and 120 mm. Calculate the contact pressure when an adhesionforce of 380 Kgf is applied.

Solution :First, let's solve problem 15:Given data:diameter of larger disc (D1)= 480 cmdiameter of…

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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段階的に解決し、人工知能を使用せず、優れた仕事を行います
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SOLVE STEP BY STEP IN DIGITAL FORMAT
15. In a two-disc coupling the diameters are 480cm and 30cm.
Calculate the engine torque transmitted for a contact pressure of 500
Kg where the adhesion coefficient is 0.40.
16. In a single disc coupling the external and internal diameters are
180 and 120 mm. Calculate the contact pressure when an adhesion
force of 380 Kgf is applied.

Expert Solution

Step 1: Step 1

Solution :

First, let's solve problem 15:

Given data:

diameter of larger disc (D₁)= 480 cm

diameter of smaller disc (D₂)= 30 cm

Contact Pressure(P)= 500 kg

Adhesion coefficient $open parentheses mu close parentheses$ = 0.40 To

find:

Engine torque transmitted

Engine torque (T) is calculated by using the formula:

$T equals fraction numerator P cross times open parentheses D subscript 1 superscript 2 minus D subscript 2 superscript 2 close parentheses over denominator open parentheses 4 cross times mu close parentheses end fraction$

Substitute the given values into the formula:

$T equals fraction numerator 500 space k g cross times open parentheses 480 c m squared minus 30 c m squared close parentheses over denominator open parentheses 4 cross times 0.40 close parentheses end fraction T equals fraction numerator 500 open parentheses 230400 space c m squared minus 900 space c m squared close parentheses over denominator 1.6 end fraction T equals 71718750 space k g space c m squared$

Therefore, the engine torque transmitted is approximately 71718750 kg cm²

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