Situation 6. A square footing 2.5 m x 2.5 m supports a square column 300 mm x 300mm at its center. Concrete cover to bar centroid = 100 mm. Ultimate load.combination is 1.2D + 1.6L.Column loads are service conditions:DL= 680 KNLL = 400 KNf'c = 20.7 MPa fy= 415 MPa15.16.17.Calculate the minimum required thickness of the slab to be adequate againstwide beam shear.320 mm.420 mmA.B.C.D.300 mm.400 mm.Calculate the nominal punching-shear stress acting at the critical section ofthe footing slab in MPa if the thickness of the slab is 450 mm.A. 1.99B. 1.49C. 1.69D.2.09Calculate the required spacing (in mm) of 16-mm-dia. flexure bars for 1-m stripof the footing slab if the thickness of the slab is 450 mm.A. 150C. 170B.160D.180

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Situation 6. A square footing 2.5 m x 2.5 m supports a square column 300 mm x 300 mm at its center. Concrete cover to bar centroid = 100 mm. Ultimate load. combination is 1.2D + 1.6L. Column loads are service conditions: DL= 680 kN LL 400 KN f'c = 20.7 MPa fy 415 MPa. 15. 16. 17. Calculate the minimum required thickness of the slab to be adequate against wide beam shear. 320 mm 420 mm A. B. C. D. Calculate the nominal punching-shear stress acting at the critical section of the footing slab in MPa if the thickness of the slab is 450 mm. A. 1.99 B. 1.49 150 160 300 mm 400 mm C. D. 1.69 2.09 Calculate the required spacing (in mm) of 16-mm-dia. flexure bars for 1-m strip of the footing slab if the thickness of the slab is 450 mm. A. C. 170 B. D. 180

Situation 6. A square footing 2.5 m x 2.5 m supports a square column 300 mm x 300 mm at its center. Concrete cover to bar centroid = 100 mm. Ultimate load. combination is 1.2D + 1.6L. Column loads are service conditions: DL= 680 kN LL 400 KN f'c = 20.7 MPa fy 415 MPa. 15. 16. 17. Calculate the minimum required thickness of the slab to be adequate against wide beam shear. 320 mm 420 mm A. B. C. D. Calculate the nominal punching-shear stress acting at the critical section of the footing slab in MPa if the thickness of the slab is 450 mm. A. 1.99 B. 1.49 150 160 300 mm 400 mm C. D. 1.69 2.09 Calculate the required spacing (in mm) of 16-mm-dia. flexure bars for 1-m strip of the footing slab if the thickness of the slab is 450 mm. A. C. 170 B. D. 180

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

Situation 6. A square footing 2.5 m x 2.5 m supports a square column 300 mm x 300
mm at its center. Concrete cover to bar centroid = 100 mm. Ultimate load.
combination is 1.2D + 1.6L.
Column loads are service conditions:
DL= 680 KN
LL = 400 KN
f'c = 20.7 MPa fy= 415 MPa
15.
16.
17.
Calculate the minimum required thickness of the slab to be adequate against
wide beam shear.
320 mm.
420 mm
A.
B.
C.
D.
300 mm.
400 mm.
Calculate the nominal punching-shear stress acting at the critical section of
the footing slab in MPa if the thickness of the slab is 450 mm.
A. 1.99
B. 1.49
C. 1.69
D.
2.09
Calculate the required spacing (in mm) of 16-mm-dia. flexure bars for 1-m strip
of the footing slab if the thickness of the slab is 450 mm.
A. 150
C. 170
B.
160
D.
180

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