Show that if A reacts to form either B or C according to elementary unimolecular reactions then Show that the half-life of A is AB А В = Ак3, С or A ог [A]t =[A]oe¯(k1+k₂)t In 2 k₁ + k₂ t1/2 Show that [B]t/[C]t = k₁/k₂ for all times t. For the set of initial conditions [A]o [B]o [C]o = 0, and k₁ = 1, and k₂ 1, and k₂ = 4 plot [A], [B], and [C] as functions of time on =
Show that if A reacts to form either B or C according to elementary unimolecular reactions then Show that the half-life of A is AB А В = Ак3, С or A ог [A]t =[A]oe¯(k1+k₂)t In 2 k₁ + k₂ t1/2 Show that [B]t/[C]t = k₁/k₂ for all times t. For the set of initial conditions [A]o [B]o [C]o = 0, and k₁ = 1, and k₂ 1, and k₂ = 4 plot [A], [B], and [C] as functions of time on =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Show that if A reacts to form either B or C according to elementary unimolecular
reactions
then
Show that the half-life of A is
AB or
=
[A]t =[A]oe-(k₁+k₂)t
t1/2
or A C
=
In 2
k₁ + k2
Show that [B]/[C]t = k₁/k₂ for all times t. For the set of initial conditions [A]o = 1,
[B]o [C]o = 0, and k₁ = 1, and k₂ = 4 plot [A], [B], and [C] as functions of time on
the same graph.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d6b1f03-b4bd-4f60-ae23-d8256607755b%2Fb36db5b6-fd17-472a-b4c9-681518df4008%2Faje5c6r_processed.png&w=3840&q=75)
Transcribed Image Text:Show that if A reacts to form either B or C according to elementary unimolecular
reactions
then
Show that the half-life of A is
AB or
=
[A]t =[A]oe-(k₁+k₂)t
t1/2
or A C
=
In 2
k₁ + k2
Show that [B]/[C]t = k₁/k₂ for all times t. For the set of initial conditions [A]o = 1,
[B]o [C]o = 0, and k₁ = 1, and k₂ = 4 plot [A], [B], and [C] as functions of time on
the same graph.
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