Suppose the formation of nitrogen dioxide proceeds by the following mechanism: step elementary reaction rate constant 1 2 NO(g) - N,O2(9) 2 N,02(9) + O2(g9) → 2 NO,(9) olo Suppose also k, «k. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k.1 and k.2 for k = the reverse of the two elementary reactions in the mechanism.

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Writing the rate law implied by a simple mechanism
Suppose the formation of nitrogen dioxide proceeds by the following
mechanism:
step
elementary reaction
rate constant
1
2 NO(g) → N,O2(9)
2 N2O2(9) + O2(9) → 2 NO,(9)
olo
Suppose als0 k, «k,. That is, the first step is much slower than the second.
Write the balanced
O-0
chemical equation for the
overall chemical reaction:
믐
Write the experimentally-
observable rate law for the
overall chemical reaction.
rate = k ||
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of k1, k2,
and (if necessary) the rate
constants k-1 and k-2 for
k =
the reverse of the two
elementary reactions in
the mechanism.
||
Transcribed Image Text:Writing the rate law implied by a simple mechanism Suppose the formation of nitrogen dioxide proceeds by the following mechanism: step elementary reaction rate constant 1 2 NO(g) → N,O2(9) 2 N2O2(9) + O2(9) → 2 NO,(9) olo Suppose als0 k, «k,. That is, the first step is much slower than the second. Write the balanced O-0 chemical equation for the overall chemical reaction: 믐 Write the experimentally- observable rate law for the overall chemical reaction. rate = k || Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for k = the reverse of the two elementary reactions in the mechanism. ||
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