A 50:50 by mass mixture of molten KCl and NaBr is electrolyzed under an applied dc voltage. Predict theprimary products at the respective electrodes.Given below are standard reduction potential values:Cl₂/CI¯ = +1.36 VBr2, Br +1.07 VK+/K = -2.92 VNa+/Na = -2.71 VCathode: Br2, Anode: KO Cathode: Br2, Anode: NaCathode: Cl₂, Anode: KCathode: Cl₂, Anode: Na

NaBr and KCl is Electrolyed. Ions produced are Na+ , K+ , Cl- and Br-. As we know, in electrolysis,…

ry products at the respective electrodes. below are standard reduction potential values: = +1.36 V Br₂, Br = +1.07 V = -2.92 V Na*/Na = -2.71 V Cathode: Br₂, Anode: K Cathode: Br₂, Anode: Na Cathode: Cl₂, Anode: K Cathode: Cl₂, Anode: Na

ry products at the respective electrodes. below are standard reduction potential values: = +1.36 V Br₂, Br = +1.07 V = -2.92 V Na*/Na = -2.71 V Cathode: Br₂, Anode: K Cathode: Br₂, Anode: Na Cathode: Cl₂, Anode: K Cathode: Cl₂, Anode: Na

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A 50:50 by mass mixture of molten KCl and NaBr is electrolyzed under an applied dc voltage. Predict the
primary products at the respective electrodes.
Given below are standard reduction potential values:
Cl₂/CI¯ = +1.36 V
Br2, Br +1.07 V
K+/K = -2.92 V
Na+/Na = -2.71 V
Cathode: Br2, Anode: K
O Cathode: Br2, Anode: Na
Cathode: Cl₂, Anode: K
Cathode: Cl₂, Anode: Na

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