Find the pH, if E = - 0.70 V.Table 7.2 Stundard potertiabat 298 K. (a) in dectrochemical erderReductien half ractionRecuction half-mactionEIVStrongly onidiringH + Zir +2J0, + H,0Se+2S+0.156.070,2H+ 0,+HOS,o +220+2000+2.05aby definitienCe CIn leSe+ SnAu+ Au-014N + NICa+ CeIn+ In023+140Mno,+ H+-+Me"+4H0Mn" +eMe+151Au+ Aa, 2aCro + 14H +be +20+7H,00,+H0+ 0, 20H0,+4r 4 201.40In le+1241231.23-040-044Mao, + Ma+21,0-044S+In ln097NO; +r NO- 21,0074Za+ Zn-76+06NO, +2rr NO, + HO21,0+ 1, +20r+0.79Mn+2e Mn-LIE--L19O+H0+-r +20+0.76-163A AlMn +21,0+ 2 Meo,4O1.79-2091,+ 21+0.54M+rMg-2+0.3224252NICOH + H0-NOI), +OrNaeNa-287+0.00-2.09291Ra a292+0.34-292-2.9340.222.93-3.05 Given the following reactions:Anode: NO3- + 2H+ + e- --> NO2 +H2OCathode: 2H+ + 2e- --> H2Redox:2NO2(g) + 2H2O (I)--> 2NO3-(aq) + 2H+(aq) +H2(g)Conditions:[0.15 atm][0.18 atm][0.1 M][0.67 atm]Find the pH, if E = - 0.70 V.%3D

Answered: Image /qna-images/answer/e5ffd3cf-0ef7-4c8d-b544-72562035b1c4.jpg

Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 2NO2(g) + 2 H2O (I) --> 2NO3-(aq) + 2H+(aq) + Redox: H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.67 atm] Find the pH, if E = - 0.70 V.

Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 2NO2(g) + 2 H2O (I) --> 2NO3-(aq) + 2H+(aq) + Redox: H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.67 atm] Find the pH, if E = - 0.70 V.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Find the pH, if E = - 0.70 V.
Table 7.2 Stundard potertiabat 298 K. (a) in dectrochemical erder
Reductien half raction
Recuction half-maction
EIV
Strongly onidiring
H + Zir +2J0, + H,0
Se+2S
+0.15
6.07
0,2H+ 0,+HO
S,o +220
+20
00
+2.05
aby definitien
Ce C
In le
Se+ Sn
Au+ Au
-014
N + NI
Ca+ Ce
In+ In
023
+140
Mno,+ H+-+Me"+4H0
Mn" +eMe
+151
Au+ A
a, 2a
Cro + 14H +be +20+7H,0
0,+H0+ 0, 20H
0,+4r 4 20
1.40
In le
+124
123
1.23
-040
-044
Mao, + Ma+21,0
-044
S+
In ln
097
NO; +r NO- 21,0
074
Za+ Zn
-76
+06
NO, +2rr NO, + HO
21,0+ 1, +20r
+0.79
Mn+2e Mn
-LIE
--L19
O+H0+-r +20
+0.76
-163
A Al
Mn +21,0+ 2 Meo,4O
1.79
-209
1,+ 21
+0.54
M+rMg
-2
+0.32
24
252
NICOH + H0-NOI), +Or
NaeNa
-287
+0.00
-2.09
291
Ra a
292
+0.34
-292
-2.93
40.22
2.93
-3.05

Given the following reactions:
Anode: NO3- + 2H+ + e- --> NO2 +
H2O
Cathode: 2H+ + 2e- --> H2
Redox:
2NO2(g) + 2
H2O (I)
--> 2NO3-(aq) + 2H+(aq) +
H2(g)
Conditions:
[0.15 atm]
[0.18 atm]
[0.1 M]
[0.67 atm]
Find the pH, if E = - 0.70 V.
%3D

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