Find the pH, if E = - 0.70 V.Table 7.2 Stundard potertiabat 298 K. (a) in dectrochemical erderReductien half ractionRecuction half-mactionEIVStrongly onidiringH + Zir +2J0, + H,0Se+2S+0.156.070,2H+ 0,+HOS,o +220+2000+2.05aby definitienCe CIn leSe+ SnAu+ Au-014N + NICa+ CeIn+ In023+140Mno,+ H+-+Me"+4H0Mn" +eMe+151Au+ Aa, 2aCro + 14H +be +20+7H,00,+H0+ 0, 20H0,+4r 4 201.40In le+1241231.23-040-044Mao, + Ma+21,0-044S+In ln097NO; +r NO- 21,0074Za+ Zn-76+06NO, +2rr NO, + HO21,0+ 1, +20r+0.79Mn+2e Mn-LIE--L19O+H0+-r +20+0.76-163A AlMn +21,0+ 2 Meo,4O1.79-2091,+ 21+0.54M+rMg-2+0.3224252NICOH + H0-NOI), +OrNaeNa-287+0.00-2.09291Ra a292+0.34-292-2.9340.222.93-3.05 Given the following reactions:Anode: NO3- + 2H+ + e- --> NO2 +H2OCathode: 2H+ + 2e- --> H2Redox:2NO2(g) + 2H2O (I)--> 2NO3-(aq) + 2H+(aq) +H2(g)Conditions:[0.15 atm][0.18 atm][0.1 M][0.67 atm]Find the pH, if E = - 0.70 V.%3D

Answered: Image /qna-images/answer/e5ffd3cf-0ef7-4c8d-b544-72562035b1c4.jpg

Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 2NO2(g) + 2 H2O (I) --> 2NO3-(aq) + 2H+(aq) + Redox: H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.67 atm] Find the pH, if E = - 0.70 V.

Given the following reactions: Anode: NO3- + 2H+ + e- --> NO2 + H2O Cathode: 2H+ + 2e- --> H2 2NO2(g) + 2 H2O (I) --> 2NO3-(aq) + 2H+(aq) + Redox: H2(g) Conditions: [0.15 atm] [0.18 atm] [0.1 M] [0.67 atm] Find the pH, if E = - 0.70 V.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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