For the following half-reactions, answer the following questions below E = +1.953 V Co*(aq) + e- Co*(aq) Fe*(aq) + e → • Fe²*(aq) E = +0.769 V 1(aq) + 2e" → 21~(aq) E = +0.534 V E° = -0.127 V E = -0.402 V Pb²*(aq) + 2e¯ Pb(s) > Cd?+(aq) + 2e" Cd(s) Mn** (aq) + 2е" Mn(s) E° = -1.182 V
For the following half-reactions, answer the following questions below E = +1.953 V Co*(aq) + e- Co*(aq) Fe*(aq) + e → • Fe²*(aq) E = +0.769 V 1(aq) + 2e" → 21~(aq) E = +0.534 V E° = -0.127 V E = -0.402 V Pb²*(aq) + 2e¯ Pb(s) > Cd?+(aq) + 2e" Cd(s) Mn** (aq) + 2е" Mn(s) E° = -1.182 V
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![g. Which ion/s can be reduced by Ph?
h. Which metal/s can be oxidized by Fe*?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F375f3253-691e-4998-96d3-4e3388aa26bc%2F23f6ad29-6e9a-4212-92fd-0b1d4c433436%2Fuhttfmi_processed.png&w=3840&q=75)
Transcribed Image Text:g. Which ion/s can be reduced by Ph?
h. Which metal/s can be oxidized by Fe*?
![For the following half-reactions, answer the following questions below
E° = +1.953 V
Co+(aq) + e →Co2+(aq)
- Fe?+(aq)
Fe*(aq) + e-
E = +0.769 V
I,(aq) + 2e- - 21-(aq)
E = +0.534 V
Pb²*(aq) + 2e¯
Pb(s)
E = -0.127 V
>
→ Cd(s)
Cd²*(aq) + 2e-
Mn2+(aq) + 2e- → Mn(s)
E = -0.402 V
E° = -1.182 V](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F375f3253-691e-4998-96d3-4e3388aa26bc%2F23f6ad29-6e9a-4212-92fd-0b1d4c433436%2F34aerbm_processed.png&w=3840&q=75)
Transcribed Image Text:For the following half-reactions, answer the following questions below
E° = +1.953 V
Co+(aq) + e →Co2+(aq)
- Fe?+(aq)
Fe*(aq) + e-
E = +0.769 V
I,(aq) + 2e- - 21-(aq)
E = +0.534 V
Pb²*(aq) + 2e¯
Pb(s)
E = -0.127 V
>
→ Cd(s)
Cd²*(aq) + 2e-
Mn2+(aq) + 2e- → Mn(s)
E = -0.402 V
E° = -1.182 V
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