Rhino viruses typically cause common colds. In a test of the effectiveness ofechinacea, 32 of the 39 subjects treated with echinacea developed rhinovirusinfections. In a placebo group, 81 of the 94 subjects developed rhinovirus infections.Use a 0.05 significance level to test the claim that echinacea has an effect onrhinovirus infections. Complete parts (a) through (c) below.b. Test the claim by constructing an appropriate confidence interval.The 95% confidence interval is< (P, - P2) <(Round to three decimal places as needed.)

Given information- We have given two samples. Sample proportion is- Point estimate is given by-…

Answered: Rhino viruses typically cause common…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of freshman takes a reading comprehension test and their scores are summarized below. Sample scores: 16, 8, 8, 6, 9, 11, 13, 9, 10 a. if the mean for the general population on this test is m=12, can you conclude that this sample is significantly different from the population. Test with a=.05 b. Calculate a 90% confidence interval around your mean.
Allen's hummingbird has been studied by zoologist Bill Alther. Suppose a small group of 15 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x=3.15 grams. Based in previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with o=0.22 gram. find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit= upper limit= margin of error=
study of 420,077 cell phone users found that 133 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0236% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.
University personnel are concerned about the sleeping habits of students and the negative impact on academic performance. In a random sample of 377 U.S. college students, 209 students reported experiencing excessive daytime sleepiness (EDS). Is there sufficient evidence to conclude that more than half of U.S. college students experience EDS? Use a 5% level of significance STATE: What is a 90% confidence interval estimate for the proportion of all of U.S. college students who experience excessive daytime sleepiness? PLAN: State the name of the appropriate estimation procedure (e.g. one-sample t confidence interval for estimating the mean difference) Note: You have already described the parameter being estimated in Part A, so you don't have to repeat it here.
Ms. Rains believes more seniors from PLD plan to attend college than seniors at Lafayette. In a random sample of 35 PLD seniors, 21 responded they plan to attend college. In a random sample of 32 Lafayette seniors only 17 responded they plan to attend college. Using a 95% confidence interval, predict the true difference in the proportion of seniors at PLD and Lafayette who plan to attend college and comment on Ms. Rains' belief.
Dr. Dream, an expert in infectious diseases, wanted to estimate theproportion of the adult population in the U.S. that received a flu vaccine.They randomly sample 866 individuals and 388 of them received a fluvaccine. They decide to report a 90% confidence interval for the populationproportion.a. What is the value of the standard error? b. What is the value of the margin of error?
A learn-to-type software program claims that it can improve your typing skills. To test the claim and possibly help yourself out, you and eight of your friends decide to try the program and see what happens. Use the table below to construct an 85%85% confidence interval for the true mean change in the typing speeds for people who have completed the typing program. Let Population 1 be the typing speed before taking the program and Population 2 be the typing speed after taking the program. Round the endpoints of the interval to one decimal place, if necessary. Typing Speeds (in Words per Minute) Before After 42 33 41 54 31 50 30 48 41 31 49 52 34 54 48 49 39 48
Use the technology of your choice to obtain the required Tukey multiple-comparison confidence intervals with a family confidence level of 0.95. Hospital Stays. The U.S. National Center for Health Statistics collects data on length of stay in noninstitutional, short-stay hospitals by sex and age. Results are published in Vital and Health Statistics. Independent random samples of Americans were taken to compare the lengths of stay (in days) for males and females in four age groups (15–24 years, 25–34 years, 35–44 years, and 45–64 years). Obtained for a two-way ANOVA on these data and also supplies a table of cell and marginal means.
Eight subjects were asked to perform a simple puzzle-assembly task under customary conditions and under conditions of stress. During the stressful condition, the subjects were told that a mild shock would be delivered 3 minutes after the start of the experiment and every 30 seconds thereafter until the task is completed. Blood pressure readings were taken under both conditions. The data are recorded in Table 2 below. We wish to estimate the difference of means with a 95 percent confidence interval. a. Degrees of freedom and t-value are b. Margin of error and confidence interval c. We may state with 95 percent confidence that average blood pressure during conditions of stress is i. Significantly different from average blood pressure during normal conditions ii. Not significantly different from average blood pressure during normal conditions
We have conducted a one sided hypothesis test with a significance level a = 0.05. We would like to also construct a confidence interval with an equivalent level so that we can compare our results. What should the confidence level of this interval be? (Note: Do not include the percent sign.)
University personnel are concerned about the sleeping habits of students and the negative impact on academic performance. In a random sample of 377 U.S. college students, 209 students reported experiencing excessive daytime sleepiness (EDS). Is there sufficient evidence to conclude that more than half of U.S. college students experience EDS? Use a 5% level of significance. What is a 90% confidence interval estimate for the proportion of all of U.S. college students who experience excessive daytime sleepiness? PLAN: State the name of the appropriate estimation procedure (e.g. one-sample t confidence interval for estimating the mean difference). You have already listed the conditions, now check the condition for the normality of the sampling distribution of p-hat for confidence interval estimation

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