In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to2416subjects randomly selected from an online group involved with ears.1010surveys were returned. Construct a90%confidence interval for the proportion of returned surveys. **Sample Data Exercise: Confidence Level Calculation**In a study of cell phone use and brain hemispheric dominance, researchers conducted an Internet survey. This survey was emailed to 2,416 subjects who were randomly selected from an online group focused on auditory-related topics. Out of the total, 1,010 surveys were successfully returned. **Task:** Construct a 90% confidence interval for the proportion of returned surveys.**Additional Information:** - You may need to refer to a table of z-scores for detailed calculations.(Note: The image includes an icon prompt suggesting the availability of a z-score table; ensure you have access to such a table for accurate calculations.)

It is given that, n=2416 and x=1010.

In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2416 subjects randomly selected from an online group involved with ears. 1010 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys.

In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2416 subjects randomly selected from an online group involved with ears. 1010 surveys were returned. Construct a 90% confidence interval for the proportion of returned surveys.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A graduate student is interested in how viewing different types of scenes affects working memory. For his study, he selects a random sample of 36 adults. The subjects complete a series of working memory tests before and after walking in an urban setting. Before the walk, the mean score on the test of working memory was 9.1. After the walk, the mean score was 1.4 higher. The graduate student has no presupposed assumptions about how viewing different types of scenes affects working memory, so he formulates the null and alternative hypotheses as: H00 : μDD = 0 H11 : μDD ≠ 0 Assume that the data satisfy all of the required assumptions for a repeated-measures t test. The graduate student calculates the following statistics for his hypothesis test: Mean difference (MDD) 1.4 Estimated population standard deviation of the differences (s) 1.6 Estimated standard error of the mean differences (sMDMD) 0.2667 Degrees of freedom (df) 35 The t statistic 5.25 The critical values of t…
A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 44 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 49 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 4.1. From previous studies, it is known that ?1 = 1.5 and ?2 = 2.0. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance. Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement.
See attachment
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 24.4 with a standard deviation of 3.8, while the 200 students in group 2 had a mean score of 15.7 with a standard deviation of 3. Complete parts (a) and (b) below. (a) Determine the 95% confidence interval for the difference in scores, µ, - H3. Interpret the interval. The lower bound is The upper bound is (Round to three decimal places as needed.)
To test the fairness of law enforcement in its area, a local citizens group wanted to know whether women and men are unequally likely to get speeding tickets. 400 randomly selected adults were phoned and asked whether or not they had been cited for speeding in the last year. using the results in the following table and a 0.10 level of significance Men ticket =35, Men not ticketed= 144 women ticketed= 22, women not ticketed = 199 Compute the test statistic
A college administrator is interested in determining the proportion of students who receive some sort of financial aid. Instead of examining the records for all students, the administrator randomly draws 120 students and finds that 48 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid.
In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mauled to 2652 subjects randomly selected from an online group involved with ears. 1145 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys.
17
A study examined the interactions in a children's museum. (Interactions by visitors to the museum included show-and-tell, learning, teaching, refocusing, participatory play, advocating, and disciplining interactions.) Researchers observed a sample of 154 meaningful interactions, of which 73 were led by children and 81 were led by adult caregivers the target point estimate is 0.474 what is The 90% confidence interval?
In a study by Sallie Mae and Gallup, 323 of the 569respondents said that they paid for their education by taking out student loans. Find a 95% confidence interval for the proportion of students who paid for their education by taking out student loans.
A lawyer researched the average number of years served by 45 different justices on the Supreme Court. The average number of years served was 13.8 years with a standard deviation of 7.3 years. What is the 95% confidence interval for the average number of years served by all Supreme Court justices? Question 6 options: 1) (11.7,15.9) 2) (11.8,15.8) 3) (12.9,16.9) 4) (12.5,17.3)
The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"