In a randomly selected group of 650 automobile deaths, 180 were alcohol-related. Construct a 95% confidence interval for the true proportion of all automobile accidents caused by alcohol?

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Given Data: x=722 n=1762   p^=7221762=0.4098

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: The following sample data are from a normal population: 10, 8, 12, 15, 13, 11, 6, 5. What is the…

A: Given data is10,8,12,15,13,11,6,5sample size(n)=8sample mean(x¯)=10standard…

Q: In a survey of 2313 adults, 714 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given, In a survey of 2313 adults, 714 say they believe in UFOs. n=2313 x=714 Sample proportion:…

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: Of the 328 patients that completed the survey last year, 211 of them claimed to be returning…

A: The objective of the question is to identify the type of observational study conducted based on the…

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: An internet service provider sampled 540 customers and found that 55 of them experienced an…

A:

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: he standard deviation and the mean of 25 students scores are 10 and 38, respectively. Construct a…

A: Given that  Sample size (n) = 25 Mean (x¯) = 38 Standard deviation (s) = 10 Confidence level (C) =…

Q: Out of 400 people sampled, 276 had kids. Based on this, construct a 90% confidence interval for the…

A: For 90% confidence intervalα=1-CI=1-0.90=0.10So, zα2=z0.102=z0.05=1.645

Q: One year’s survey results, of 1525 respondents, 846 said that they expected difficulty finding a…

A:

Q: study of 30 college students showed that 25 are binge watching series. Find a 95% confidence…

A: given data  n = 30  x = 25 95% ci for p  = ?

Q: Out of 100 people sampled, 40 had kids. Based on this, construct a 99% confidence interval for the…

A: From given data we have : x=40 n=100 thus, p^=xn  =40100  =0.4

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.