According to the Centers for Disease Control and Prevention, 33.5% of U.S. adults have high LDL, or "bad"cholesterol. Suppose we sample 240 adults, out of which 81 have high LDL.Based on our sample, what is our estimate for the population proportion of adults with higha.b.C.LDL?What is the standard error for our estimate?Using your answers for parts a and b, construct a 95% confidence interval to estimate thepopulation proportion. Can we conclude that the percentage of those that have high LDL is higherthan 33.5%?d.Test the CDC's claim that the percentage of those that have high LDL is higher than 33.5% atthe a = 0.05 level. Report your p-value and conclusion.

The hypothesized percentage (or proportion) of US adults with LDL, p0=33.5%.The sample size, i.e.,…

Answered: According to the Centers for Disease…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Oregon had 714 complaints of identity theft out of 3449 consumer complaints. Does this data provide enough evidence to show that Oregon had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: P ?v Ha: P ? Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Ho. O Since the p-value is greater than .05, reject Ho- O Since the p-value is less than .05, fail to reject Ho- Interpret the results. O At the 5% level of significance, there is not enough evidence to show that the proportion of complaints due to identity theft in Oregon is less than 20%. O At…
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