A company manufacturing some medicine tablets with the Average weight of 500 mg and population variance of 36 mg. A quality officer in a company wants to investigate whether the weight of Paracetamol tablets is differed from 500 mg. To investigate He taken 50 tablets at the time of manufacturing and find that the average weight of 50 tablets is 504.5 mg. Make the hypothesis test that the average weight of tablets is differ from or not at 95% confidence level. INSTRUCTIONS: You can perform this exercise in Minitab? the exercise is already solved! But I just want to see how to do it in Minitab, please!
A company manufacturing some medicine tablets with the Average weight of 500 mg and population variance of 36 mg. A quality officer in a company wants to investigate whether the weight of Paracetamol tablets is differed from 500 mg. To investigate He taken 50 tablets at the time of manufacturing and find that the average weight of 50 tablets is 504.5 mg.
Make the hypothesis test that the average weight of tablets is differ from or not at 95% confidence level.
INSTRUCTIONS:
You can perform this exercise in Minitab? the exercise is already solved!
But I just want to see how to do it in Minitab, please!
Note:
the exercise is already solved! as seen in the image I attached, I just want to see it solved in minitab!
(with pictures, or sreenshots) however, but I want to see the procedure :)
![Step 1- Hypotheses -:
Null hypothesis H,: u = 500 (or) The population average weight of tablets is equal to 500 mg
Alternative hypothesis H;: u# 500 (or) The population average weight of tablets is not equal to 500 mg
Step 2- Calculation of z test statistic:
Given values are,
x bar = sample mean = 504.5 mg
H = population mean = 500 mg
o = Population standard deviation =6 [ because population variance o = 36]
%3D
n= sample size = 50
Substitute the above values in z test statistic formula as given
= z
vn
504.5-500
4.5
6/7.071
4.5
0.85
5.30
Thus, the z test statistic is 5.30](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda00748f-2fe5-43e3-9a7d-69ff084c8531%2F0f6a4586-f847-456c-836b-3b622ced965e%2Ftvkn9da_processed.png&w=3840&q=75)

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Step by step
Solved in 3 steps with 1 images
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