!Required informationThe pin diagram of a resistance array is shown in the given figure. Assume R = 50 Q.75 Ω43ww40 Ω· 40 ΩRwwwwwwwwRR12Find the equivalent resistance between 1 and 2.The equivalent resistance between 1 and 2 is |Ω.

To find the equivalent resistance between points 1 and 2, let's analyze the configuration of the…

Answered: ! Required information The pin diagram…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Find out the error for the given program io = 1.7e-8; % dark saturation current in amperes tc = 27; % cell temperature in degree celsius isc = 250 ; % short circuit current density A/ square meter pin = 820; % solar radiation in w/square meter k =1.381e-23; % Boltzmann's gas constant e= 1.602e-19; % electronic charge t= 273+tc % cell temperature in Kelvin vmax=0.526; % mayi mum voltage in volts imax = (e*vmax)*(isc+io)/(k*t+e*vmax) pmax= vmax*imax efficiency = (pin/pmax)*100 O error in efficiency O no error O Error in pmax O Error in imax O no output
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Q: Figure 2 shows a typical mast from a modern racing yacht. It is built in the form of a thin-walled tube (hallow cylinder). To win long-haul ocean races, these yachts need to have every advantage that high-performance materials can give, in terms of maximum stiffness (must not easily deflect), plus minimum weight as possible. The following are the equations to use: 1(F13 8 == 8 EI and I = ar³t, A = 2art assume l and cross section are fixed but thickness t is free to change. • Drive the performance index for this problem • Use table 1 to select top three materials with the best performance index. Figure 2 Table. 1 Data for Tube of Given Stiffness p (Mg.m 3) 2.0 Material E (GPa) GFRP 12 Steel 7.8 200 Wood 0.6 12 Aluminum alloy Titanium alloy 2.7 69 4.5 120
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In the network shown, Find the current I and the power supplied by the voltage source, for V = 6 V. + v(* ` 20 k2 Select one: a. I = 0.45 mA, P = - 4.05 mW b. I = 0.2 mA, P = - 0.8 mW c. I = 0.3 mA, P = - 1.8 mW %3D d. I = 0.4 mA, P = - 3.2 mW e. I = 0.6 mA, P = - 7.2 mW
27 of 32 A thermistor obeys the equation R(T) = A*exp(B/T) ohms, where A = 0.02 Q and B = 3700 K. When the thermistor resistance is 2 kQ, its temperature is O 370 K O 467 °C O 48.3 °C O 321 °C
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! Required information The pin diagram of a resistance array is shown in the given figure. Assume R = 50 Q. 75 Ω 4 3 ww 40 Ω · 40 Ω R wwwww www R R 1 2 Find the equivalent resistance between 1 and 2. The equivalent resistance between 1 and 2 is | Ω.