Regarding the "diffusion across a selectively permeable membrane" experiment, how would you know if starch left the tubing and entered the surrounding solution?
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- https://www.youtube.com/watch?v=YP8hYJcIRuo Explain how the experiment shown models a semi-permeable membrane. What direct, observable evidence do we have that starch was not able to diffuse through the membrane?after a 5 g onion sample is divided into two equal parts, heat treatment to one of these partsit is being implemented. Then both heat-treated and non-treated parts are 10 times their weightit is ground in an environment containing as much buffer and the determination of pyruvate in the supernatants obtainedit's being done.a) As a result of measurements taken at 520 nm; absorbance value for the heat-treated sample;it was found that the absorbance value in the sample that was not heat treated was 0.123 and the absorbance value in the sample that was not heat treated was 0.520.The equation of the calibration accuracy for pyruvate is that y = 0.1367x – 0.001 (nmol/mL)according to the onion sample; a) independent of alinase activity; b) dependent on alinase activityand c) calculate the total pyruvate amounts in terms of nmol/g of onion.b) How is there a relationship between the activity of the enzyme allinase in onions and the amount of pyruvate?Dec,please explain.The reults for the macroscopic part: 0.30M glycerin – solution was translucent (could see text behind the test tube) 0.15M NaCl – solution was opaque (could not see text behind the test tube) 0.30M NaCl – solution was opaque (could not see text behind the test tube) 0.15M glucose – solution was translucent (could see text behind the test tube) 0.30M glucose – solution was opaque (could not see text behind the test tube) 0.30M Urea – solution was translucent (could see text behind the test tube) Results for microscopic part: 0.30M glycerin – no cells present 0.15M NaCl – normal sized cells 0.30M NaCl – crenated (shrunken and star-shaped) cells 0.15M glucose – no cells present 0.30M glucose – normal sized cells 0.30M Urea – no cells present Determine the osmolarity (hypoosmotic, isosmotic, or hyperosmotic) and tonicity (hypotonic, isotonic, hypertonic) of the following solutions.In which solutions did the osmolarity NOT match the tonicity? For those solutions, why did the osmolarity…
- Can sucrose pass freely through the membrane of a dialysis tube? Explain. (Biochem)Inside a beaker, dialysis membrane A is filled with a 50% glucose solution and dialysis membrane B is filled with a 50% NaCl solution. Both bags are put into beakers containing 100% water. Which of the following choices is correct? (hint: the dialysis membrane is only permeable to water) a) For both solutions, it is isosmotic, and hypotonic so water flows into the membrane.b) For both solutions, it is isosmotic, and isotonic so there is not net flow of waterc) For both solutions, it is hyposmotic, and hypotonic so water flows into the membraned) For both solutions, it is hyperosmotic, and hypertonic so water flows into the membranee) For both solutions, it is hyposmotic, and hypertonic so water flows out of the membraneGiven this, if you used 6g of vitamin Z powder to make 20 ml of solution, what is the % concentration of this solution? (I gave the image since I don't know if that info is needed to solve this question.)It also gives a follow-up, if you can help here too: You work in a lab as a summer student. One of your tasks is to make sure that there is enough cell culture medium containing antibiotics to grow bacteria. One day you realize that there is only 5 ml of 10% Antibiotic stock solution in the freezer. You decide to use it all to prepare the working culture medium with 0.01% antibiotic. In the lab there is plenty of growth medium without antibiotics. (Note: dilution in medium is like dilution in water). You remember the equation to make dilutions of stock solutions. You usually use this formula to calculate the required volume of a stock solution, but you realize it can apply here as well, even though the unknown is the final volume. So, you make that dilution. Given that each bacterial…
- Determine the amount of glucose in the unknown sample by plotting a standard curve of Absorbance at 620 nm on Y-axis and μg of glucose on the x-axis.While performing the experiment " Detection of ammonium sulphate in Milk", a pink color result is observed. What can we conclude from this observation?Using G-25 Sephadex beads (Fractionation range 1000-5000) KD, a sample of Vitamin B12 (MW ~1500 KD) will be: Fully excluded Partially included Fully included the activity of lysozyme was determined by looking at the increase in light scattering per unit time increase in absorbance per unit time. decrease in absorbance per unit time. increase in concentration per unit time.
- for the following scenario, DRAW the situation depicted, INDICATE which solution is hypertonic, hypotonic or isotonic (if applicable), and then show with ARROWS which way water will move. then write your response in complete sentences, thoroughly explaining and justifying your arrows. a. ouch! sore throat! it is so swollen that it is sore and it is difficult to swallow. and you have an oral presentation today. better gargle with salt water to reduce the swelling! explain why this age old technique really works, by using the concept of osmosisFor the following scenario you must draw the situation depicted, indicate which solution is hypertonic, hypotonic or isotonic (as applicable), and then show with arrows which way water will move. Then you must write your response in complete sentences, thoroughly explaining and justifying your arrows. a. Ouch! Sore throat! It is so swollen that it is sore and it is difficult to swallow. And you have an oral presentation today. Better gargle with salt water to reduce the swelling! Explain why this age old technique really works, by using the concept of osmosis.Table 1 - Comparison of the effect of catechol concentration on the amount of product formed. Absorbance Potato extract Absorbance 0 mins after 30mins (2nd reading) (mL) 1st reading 1 Tube # la blank 2a 3a 4a 1 1 1 dH₂O Catechol (mL) (mL) 7 5 3 1 0 2 4 6 0.00 0.060 0.033 0-05-2 Q4) Give 2 reasons for adding dH₂O to these tubes in Table 1? Time for reading: 3:21 -0.11 Absorbance: Time for reading: 3.36 Q5) Tube la serves as a control, but why is this control needed? Absorbance: 0.197 Time for reading: 3.37 Based on the data from Table 1 answer these questions: Q1) What is the name of the enzyme found in potato extract? Answer: catechol Q2) What is the substrate? Answer: THO Q3) Name of product of this enzyme catalyzed reaction? Answer: Absorbance: 0.152 Time for reading: 3:39 Absorbance: . 166 ness Catechol Benzoquinone Subtract 1st from 2nd reading -0.01 0-137 0.11.19 0.119 Q6) Notice that your 1st absorbance reading in tubes 2a-4a are quite similar but it then becomes very different…