References A 3.41 g sample of iron ore is transformed to a solution of iron(II) sulfate, FeSO4. This solution is titrated with 0.160 M K2 Cr2O7 (potassium dichromate). If it requires 42.8 mL of potassium dichromate solution to titrate the iron(II) sulfate solution, what is the percentage of iron in the ore? The reaction is 6FESO, (ag) + K, Cr2O7(ag) + 7H,SO4 (aq) → 3F22 (SO4)3 (aq) + Cr2 (SO4)3(aq) + 7H2O(1) + K2S0. (ag) Percentage = Submit Answer Try Another Version 3 item attempts remaining
References A 3.41 g sample of iron ore is transformed to a solution of iron(II) sulfate, FeSO4. This solution is titrated with 0.160 M K2 Cr2O7 (potassium dichromate). If it requires 42.8 mL of potassium dichromate solution to titrate the iron(II) sulfate solution, what is the percentage of iron in the ore? The reaction is 6FESO, (ag) + K, Cr2O7(ag) + 7H,SO4 (aq) → 3F22 (SO4)3 (aq) + Cr2 (SO4)3(aq) + 7H2O(1) + K2S0. (ag) Percentage = Submit Answer Try Another Version 3 item attempts remaining
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Iron Ore Analysis Using Titration**
A 3.41 g sample of iron ore is transformed into a solution of iron(II) sulfate, FeSO₄. This solution is titrated with 0.160 M K₂Cr₂O₇ (potassium dichromate). If it requires 42.8 mL of potassium dichromate solution to titrate the iron(II) sulfate solution, what is the percentage of iron in the ore?
The chemical reaction involved is as follows:
\[ 6\text{FeSO}_4(aq) + \text{K}_2\text{Cr}_2\text{O}_7(aq) + 7\text{H}_2\text{SO}_4(aq) \rightarrow 3\text{Fe}_2(\text{SO}_4)_3(aq) + \text{Cr}_2(\text{SO}_4)_3(aq) + 7\text{H}_2\text{O}(l) + \text{K}_2\text{SO}_4(aq) \]
Calculate the percentage of iron in the ore using the data provided.
**Percentage =** \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\) %
**Submit Answer**
**Try Another Version**
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Transcribed Image Text:**Iron Ore Analysis Using Titration**
A 3.41 g sample of iron ore is transformed into a solution of iron(II) sulfate, FeSO₄. This solution is titrated with 0.160 M K₂Cr₂O₇ (potassium dichromate). If it requires 42.8 mL of potassium dichromate solution to titrate the iron(II) sulfate solution, what is the percentage of iron in the ore?
The chemical reaction involved is as follows:
\[ 6\text{FeSO}_4(aq) + \text{K}_2\text{Cr}_2\text{O}_7(aq) + 7\text{H}_2\text{SO}_4(aq) \rightarrow 3\text{Fe}_2(\text{SO}_4)_3(aq) + \text{Cr}_2(\text{SO}_4)_3(aq) + 7\text{H}_2\text{O}(l) + \text{K}_2\text{SO}_4(aq) \]
Calculate the percentage of iron in the ore using the data provided.
**Percentage =** \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\) %
**Submit Answer**
**Try Another Version**
*3 item attempts remaining*
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