The balanced equation for the precipitation reaction between lead ion and potassium chloride is shown below. Pb²+ (aq) + 2 KCl(aq) → PbCl₂ (s) + 2K+ (aq) Lead(II) ion is highly poisonous. To determine the amount of lead ion, a water sample was treated with excess of potassium chloride. A precipitate of lead(II) chloride was formed, weighing 80.1 µg. Determine the mass of lead (in micrograms) in the water sample. • Enter your answer with three significant figures.

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The balanced equation for the precipitation reaction between lead ion and potassium chloride is shown below.
Pb²+ (aq) + 2 KCl(aq) → PbCl₂ (s) + 2K+ (aq)
Lead(II) ion is highly poisonous. To determine the amount of lead ion, a water sample was treated with excess of potassium
chloride. A precipitate of lead(II) chloride was formed, weighing 80.1 µg. Determine the mass of lead (in micrograms) in the
water sample.
• Enter your answer with three significant figures.
Transcribed Image Text:The balanced equation for the precipitation reaction between lead ion and potassium chloride is shown below. Pb²+ (aq) + 2 KCl(aq) → PbCl₂ (s) + 2K+ (aq) Lead(II) ion is highly poisonous. To determine the amount of lead ion, a water sample was treated with excess of potassium chloride. A precipitate of lead(II) chloride was formed, weighing 80.1 µg. Determine the mass of lead (in micrograms) in the water sample. • Enter your answer with three significant figures.
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