Concentration of calcium in a sample may be determined by precipitation using the chromate ion, CrO2. Ca²+ (aq) + CrO2 (aq) → CaCrO4(s) A chemist combined 0.445 L of an unknown calcium solution with an excess of ammounium chromate. This resulted in the precipitation of calcium chromate. The mass of the precipitate was 316.4 mg. What was the molar concentration of Ca²+ in the original sample? [Ca²+] = M

Q: 0.7532 g of copper turnings (molar mass: 63.546 g∙mol–1) are reacted with excess nitric acid.…

A: Disclaimer: In order to obtain copper sulfate the acid used in excess should be sulfuric acid and…

Q: The Burke Museum at the UW is analyzing a dinosaur bone sample for the amount of calcium it…

A: The solid

Q: To measure the amount of chlorine in a well-boring fluid, an analytical chemist adds 0.130M silver…

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Q: 250.0 mg of copper(II) sulfate pentahydrate (CuSO4•5H2O, 249.69 g/mol) was dissolved in water to…

A: Since mass of CuSO4•5H2O used = 250 mg = 0.25 g              (since 1 g = 1000 mg) Hence moles of…

Q: . What mass of precipitate (in g) is formed when 55.2 mL of 0.500 M AlBr₃ reacts with excess AgNO₃…

A: As per our guidelines we can only solve first question. Please resubmit other questions as next…

Q: 100.0 mL of an aqueous solution containing 0.250 M KOH(aq) is mixed with 100.0 mL of an aqueous…

A: First of all, we need to write down the balanced chemical.  The molar mass of Fe(OH)3 = 106.87g/mol

Q: Many metal ions are precipitated from solution by the sulfide ion. As an example, consider treating…

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Q: Lead ions can be precipitated from aqueous solutions by the addition of aqueous iodide: Pb2+ (aq) +…

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Q: What mass of precipitate (in g) is formed when 85.7 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: Given precipitation reaction; FeCl3 (aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq) Given volume of…

Q: A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs…

A: A numerical problem based on quantitative analysis, which is to be accomplished.

Q: 2 The active agent in many hair bleaches is hydrogen peroxide. The amount of H₂O2 in 13.7-g of hair…

A: given, amount of hair bleach = 13.7 g For KMnO4 molarity = 0.174 M volume = 48.9 mL

Q: To measure the amount of chlorine in a well-boring fluid, an analytical chemist adds 0.5000M silver…

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Q: A mass of 0.4113 g of an unknown acid, HA, is titrated with NaOH(aq). If the acid reacts with 28.10…

A: Acid and base reacts with each other forms water and salt. This reaction is called neutralization…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 33.0 mL of…

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Q: A 25.0-mL sample of 1.00 M Calcium nitrate solution, Ca(NO3)2, is reacted with 125.0 mL of 0.300 M…

A: Limiting Reagent is the reactant which is completely consumed when a reaction goes to completion.

Q: If 19.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, how many grams of Zn(OH)₂ will be formed…

A: Given, Mass of NaOH = 19.5 g            Molarity of Zn(NO₃)₂ = 1.00 M            Volume of Zn(NO₃)₂…

Q: A 25.00 mL sample of NaOH is titrated with 21.35 mL of 0.6736 M H2SO4. What is the Molarity of the…

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Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 15.0 mL of…

A: The objective of this question is to find out the mass of the precipitate formed when a certain…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.600 M Cd(NO₃)₂ reacts with 26.0 mL of…

A: Moles = Molarity x Volume in L For Cd(NO₃)₂, Molarity=0.600 M  Volume=20.5 mL= 0.0205 L Moles =0.600…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: To measure the amount of chlorine in a well-boring fluid, an analytical chemist adds 0.180M silver…

A:

Q: what mass in grams of Zn(OH)₂ will be formed

A: Number of moles = mass/molar mass  Molarity = moles/volume(in L)  Moles = molarity × volume(in L)…

Q: How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 59.0 mL of 0.615 M…

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Q: Identify each of the following reactions as precipitation, acid-base, oxidation-reduction, or…

A: precipitation reaction => A precipitation reaction refers to the formation of an insoluble salt…

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

A:

Q: Consider the reaction: Ag⁺(aq) + Cl⁻(aq) → AgCl(s) How many grams of NaCl would be needed to…

A: Please find your solution below :

Q: If 25.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, what mass in grams of Zn(OH)₂ will be…

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Q: Generally, only the carbonates of the Group 1 elements and the ammonium ion are soluble in water;…

A: Calcium chloride  reacts with sodium carbonate to get calcium carbonate. Molarity = moles/volume of…

Q: A solution containing the water soluble salt of the radioactive element thorium can be titrated with…

A: The above topic concerns the titration of a solution containing thorium (IV) ions with oxalic acid…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.300 M Ni(NO₃)₂ reacts with 22.5 mL of…

A: According law of mass action, the same amount of mass involved in the reaction is formed as a…

Q: The concentration of SO42– ions in a 45.0 mL sample of seawater is determined by adding a solution…

A: Given information: Mass of barium sulfate = 0.315 g Volume of sample = 45.0 mL or 0.045 L

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO₃)₂ reacts with 34.5 mL of…

A: First calculate moles for both solutions. Then using mol to mol ratio, find out moles of precipitate…

Q: mass

A:

Q: How many moles of precipitate will be formed when 100 mL of 2.00 M NaBr is reacted with 70.0 mL of…

A: The mole of precipitate will be formed has to be determined

Q: According to the following reaction, how many grams of Fe(OH)2 can form from 175.0 mL of 0.227 M…

A: The given chemical reaction is,                FeCl2(aq) + 2 NaOH(aq) →  Fe(OH)2(s) + 2 NaCl(aq)…

Q: Consider the following precipitation reaction: 2 AgNO3(aq)+ MgCl2(aq) = 2AgCl(s)+ Mg(NO3)2(aq) How…

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Q: if 30.0 g of NaOH is added to  0.800L of 1.00M Zn(NO3)2, what is the mass in grams of Zn(OH)2 will…

A: The balanced equation for the given precipitation reaction is as follows.…

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion, Cro…

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.