The amount of lead ion in a solution can be determined by gravimetric analysis using chemical reaction below. 3Pb²+ (aq) + 2PO4³ (aq) → Pb3(PO4)2 (S) If 500.0 mL of solution is treated with excess Na-PO, and 2 excess Na3PO4 and 257 mg of lead (II) phosphate (811.5427 g/mol) is collected, what was the concentration of the original solution? wing 800 godmus a. 5.56 x 103 M b. 1.90 x 10³ M c. 6.33 x 104 M d. 1.85 x 103 M plod eidt sot noiloutient seedt vollot sesal

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The amount of lead ion in a solution can be determined by gravimetric analysis using the
chemical reaction below.
3Pb²+ (aq) + 2PO4 (aq) → Pb3(PO4)2 (S)
If 500.0 mL of solution is treated with excess Na3PO4 and 257 mg of lead (II) phosphate
(811.5427 g/mol) is collected, what was the concentration of the original solution?
ava12
MOTT
a. 5.56 x 10-³ M
b. 1.90 x 10³ M
c. 6.33 x 10 M
d. 1.85 x 10³ M
iqi
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ol
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TUR
Transcribed Image Text:The amount of lead ion in a solution can be determined by gravimetric analysis using the chemical reaction below. 3Pb²+ (aq) + 2PO4 (aq) → Pb3(PO4)2 (S) If 500.0 mL of solution is treated with excess Na3PO4 and 257 mg of lead (II) phosphate (811.5427 g/mol) is collected, what was the concentration of the original solution? ava12 MOTT a. 5.56 x 10-³ M b. 1.90 x 10³ M c. 6.33 x 10 M d. 1.85 x 10³ M iqi FRAROO 00 Todmun V eidt tot enoitoodeni sasdt wollot sengl¶T opb Spi de 19an y ap In davekarage.od blurada con un owensodi Xum. fione S. mo pansdo of sy oy exant pento vist ol grabnog pompo es notab brus coxpd sis qils no funb brus coxpd sisingorges by ste ni alorio gribape TUR
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