What volume of 0.175 M sodium phosphate, Na3PO4, solution is necessary to completely react with 95.4 mL of 0.102 M copper (II) chloride, CuCl2?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2) Consider the precipitation reaction below:
Na;PO4 (aq) + CuCl2 (aq) → Cu3(PO4)2 (s) + NaCI (aq)
What volume of 0.175 M sodium phosphate, Na3PO4, solution is necessary to completely react
with 95.4 mL of 0.102 M copper (II) chloride, CuCl2?
a) Is your reaction balanced?
If not balance it!
b) Under the balanced chemical equation itself write down what is given for which
compound.
c) Construct the pathway of how you would approach the problem using the map shown
before (use the portion of the map that is applicable).
d) Set up the calculation using the map that you created as a guide.
e) What is your final answer to the correct number of significant figures?
Transcribed Image Text:2) Consider the precipitation reaction below: Na;PO4 (aq) + CuCl2 (aq) → Cu3(PO4)2 (s) + NaCI (aq) What volume of 0.175 M sodium phosphate, Na3PO4, solution is necessary to completely react with 95.4 mL of 0.102 M copper (II) chloride, CuCl2? a) Is your reaction balanced? If not balance it! b) Under the balanced chemical equation itself write down what is given for which compound. c) Construct the pathway of how you would approach the problem using the map shown before (use the portion of the map that is applicable). d) Set up the calculation using the map that you created as a guide. e) What is your final answer to the correct number of significant figures?
Expert Solution
Step 1

Reaction

                             Na3PO4 (aq) + CuCl2 (aq) -------> Cu3(PO4)2 (s) + NaCl (aq)

(a) Balanced equation

                             2Na3PO4 (aq)     +      3CuCl2 (aq) -------> Cu3(PO4)2 (s) + 6NaCl (aq)

(b)                         0.175 M                95.4 mL of 0.102 M

 

 

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