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random sample of 130 observations is selected from a binomial population with unknown pros :p-0.6 against H, p>0.6 Use a 0.05 pre inclusion is is not sufficient evidence to reject the null hypothesis that p=0.6 an reject the null hypothesis that p- 0.6 and accept that p > 0.6 Hop-0.5 against H,: p<0.5 Use a -0.05

random sample of 130 observations is selected from a binomial population with unknown pros :p-0.6 against H, p>0.6 Use a 0.05 pre inclusion is is not sufficient evidence to reject the null hypothesis that p=0.6 an reject the null hypothesis that p- 0.6 and accept that p > 0.6 Hop-0.5 against H,: p<0.5 Use a -0.05

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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A random sample of 130 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.64. (1) Test Ho: p-0.6 against H, :p> 0.6 Use a = 0.05 test statistic z critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p= 0.6 OB. We can reject the null hypothesis that p=0.6 and accept that p > 0.6. (2) Test Ho: p-0.5 against H, p<0.5 Use a- test statistic - critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p=0.5 B. We can reject the null hypothesis that p-0.5 and accept that p < 0.5 (3) Test Ho: p-0.6 against H.: p0.6 Use a- 0.05 test statistic z positive entical z score 0.05 negative critical score The final conclusion is OA. We can reject the null hypothesis that p=0.6 and accept that p0.6. B. There is not sufficient evidence to reject the null hypothesis that p-0.6.
Transcribed Image Text:A random sample of 130 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.64. (1) Test Ho: p-0.6 against H, :p> 0.6 Use a = 0.05 test statistic z critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p= 0.6 OB. We can reject the null hypothesis that p=0.6 and accept that p > 0.6. (2) Test Ho: p-0.5 against H, p<0.5 Use a- test statistic - critical z score The final conclusion is OA. There is not sufficient evidence to reject the null hypothesis that p=0.5 B. We can reject the null hypothesis that p-0.5 and accept that p < 0.5 (3) Test Ho: p-0.6 against H.: p0.6 Use a- 0.05 test statistic z positive entical z score 0.05 negative critical score The final conclusion is OA. We can reject the null hypothesis that p=0.6 and accept that p0.6. B. There is not sufficient evidence to reject the null hypothesis that p-0.6.
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