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(a) The Treatment Sum of Squares (SST) is equal to 123 while the Total Sum of Squares (SST) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. OB. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. (b) The Treatment Sum of Squares (SST) is equal to 328 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. (c) The Treatment Sum of Squares (SST) is equal to 287 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. B. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ.

(a) The Treatment Sum of Squares (SST) is equal to 123 while the Total Sum of Squares (SST) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. OB. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. (b) The Treatment Sum of Squares (SST) is equal to 328 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. (c) The Treatment Sum of Squares (SST) is equal to 287 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. B. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Suppose the Total Sum of Squares (TotalSS) for a completely randomzied design with ?=4 treatments and ?=16 total measurements is equal to 410. In each of the following cases, conduct an ?-test of the null hypothesis that the mean responses for the 4 treatments are the same. Use ?=0.05.
(a) The Treatment Sum of Squares (SST) is equal to 123 while the Total Sum of Squares (SST) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. We can reject the nulI hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. OB. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. (b) The Treatment Sum of Squares (SST) is equal to 328 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. (c) The Treatment Sum of Squares (SST) is equal to 287 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ.
Transcribed Image Text:(a) The Treatment Sum of Squares (SST) is equal to 123 while the Total Sum of Squares (SST) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. We can reject the nulI hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. OB. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. (b) The Treatment Sum of Squares (SST) is equal to 328 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic is F = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ. (c) The Treatment Sum of Squares (SST) is equal to 287 while the Total Sum of Squares (TotalSS) is equal to 410. The test statistic isF = The critical value is F = The final conclusion is: OA. There is not sufficient evidence to reject the null hypothesis that the mean responses for the treatments are the same. OB. We can reject the null hypothesis that the mean responses for the treatments are the same and accept the alternative hypothesis that at least two treatment means differ.
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