Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Use either the traditional method or P-value method as indicated. Identify the null and alternative hypotheses, test statistic, critical value(s) or P-value (or range of P-values) as appropriate, and state the final conclusion that addresses the original claim. Choose the correct option based on the problem information. In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures. 518 548 561 523 536 499 538 557 528 563 At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours. Use the P-value method of testing hypotheses. Choose the correct P-value and conclusion based on the null hypothesis. 0 0.01 < P-value < 0.025. Reject Ho- 00.05 < P-value <0.1. Reject Ho. 00.01

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**Hypothesis Testing for Computer Component Failure Times**

Assume that a simple random sample has been selected from a normally distributed population, and test the given claim. Use either the traditional method or the P-value method as indicated. Identify the null and alternative hypotheses, test statistic, critical value(s) or P-value (or range of P-values) as appropriate, and state the final conclusion that addresses the original claim. Choose the correct option based on the problem information.

In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures:

- 518
- 548
- 561
- 523
- 536
- 499
- 538
- 557
- 528
- 563

At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours. Use the P-value method of testing hypotheses. Choose the correct P-value and conclusion based on the null hypothesis.

- \(0.01 < \text{P-value} < 0.025\). Reject \(H_0\).
- \(0.05 < \text{P-value} < 0.1\). Reject \(H_0\).
- \(0.01 < \text{P-value} < 0.025\). Fail to reject \(H_0\).
- \(0.1 < \text{P-value} < 0.2\). Reject \(H_0\).
Transcribed Image Text:**Hypothesis Testing for Computer Component Failure Times** Assume that a simple random sample has been selected from a normally distributed population, and test the given claim. Use either the traditional method or the P-value method as indicated. Identify the null and alternative hypotheses, test statistic, critical value(s) or P-value (or range of P-values) as appropriate, and state the final conclusion that addresses the original claim. Choose the correct option based on the problem information. In tests of a computer component, it is found that the mean time between failures is 520 hours. A modification is made which is supposed to increase the time between failures. Tests on a random sample of 10 modified components resulted in the following times (in hours) between failures: - 518 - 548 - 561 - 523 - 536 - 499 - 538 - 557 - 528 - 563 At the 0.05 significance level, test the claim that for the modified components, the mean time between failures is greater than 520 hours. Use the P-value method of testing hypotheses. Choose the correct P-value and conclusion based on the null hypothesis. - \(0.01 < \text{P-value} < 0.025\). Reject \(H_0\). - \(0.05 < \text{P-value} < 0.1\). Reject \(H_0\). - \(0.01 < \text{P-value} < 0.025\). Fail to reject \(H_0\). - \(0.1 < \text{P-value} < 0.2\). Reject \(H_0\).
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