Suppose a cancer treatment successfully cures the disease in 67% of cases. An oncologist is developing anew treatment that they feel will cure this cancer at a higher rate.To test the hypothesis that the new treatment is more successful than the previous treatment, a randomsample of 20 people is collected.• If the number of people in the sample that are cured is less than 16, we will not reject the nullhypothesis that pOtherwise, we will conclude that p > 0.67.0.67.Round all answers to 4 decimals.1. Calculate a =P(Type I Error) assuming that p0.67. Use the Binomial Distribution.2. Calculate B = P(Type II Error) for the alternative p = 0.82. Use the Binomial Distribution.3. Find the power of the test for the alternative p0.82. Use the Binomial Distribution.

Given information: Null hypothesis H0: p=0.67Alternate hypothesis HA: p>0.67

Answered: Suppose a cancer treatment successfully…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 150 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.05 level of significance. What are the null and alternative hypotheses? = 0.03 versus H,: p Ho: P (Type integers or decimals. Do not round.) 0.03 Because npo (1- Po) = || V 10, the normal model (Round to one decimal place as needed.) V be used to approximate the P-value.
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Previously, 4% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 4% today. She randomly selects 140 pregnant mothers and finds that 2 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? = 0.04 versus H4: p < 0.04 (Type integers or decimals. Do not round.) Ho: P Because npo (1-Po) = < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)
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Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.03 versus H4: p < 0.03 (Type integers or decimals. Do not round.) Because npo (1- Po) =|| 10, the normal model V be used to approximate the P-value. (Round to one decimal place as needed.)
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Previously, 4% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 4% today. She randomly selects 135 pregnant mothers and finds that 4 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a= 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.04 versus H,: p < 0.04 (Type integers or decimals. Do not round.) Because npo (1- Po) =U (Round to one decimal place as needed.) 10, the normal model be used to approximate the P-value.
Previously, 5% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 5% today. She randomly selects 140 pregnant mothers and finds that 5 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.05 level of significance. What are the null and alternative hypotheses? < 0.05 Họ: p = 0.05 versus H,: p (Type integers or decimals. Do not round.) Because npo (1- Po) < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)

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