Question 3. A cemented carbide tool is used to turn a part with length= 18.0 in and diameter = 3.0 in. The parameters in the Taylor equation are: n= 0.27 and C = 1200. The rate for the operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00. It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed = 0.013 in/rev. Determine: a) Cutting speed for maximum production rate, b) Tool life in min of cutting, and c) Cycle time and cost per unit of product.
Question 3. A cemented carbide tool is used to turn a part with length= 18.0 in and diameter = 3.0 in. The parameters in the Taylor equation are: n= 0.27 and C = 1200. The rate for the operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00. It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed = 0.013 in/rev. Determine: a) Cutting speed for maximum production rate, b) Tool life in min of cutting, and c) Cycle time and cost per unit of product.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Question 3.
A cemented carbide tool is used to turn a part with length = 18.0 in and diameter = 3.0
in. The parameters in the Taylor equation are: n= 0.27 and C = 1200. The rate for the
operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00.
It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed
= 0.013 in/rev. Determine:
a) Cutting speed for maximum production rate,
b) Tool life in min of cutting, and
c) Cycle time and cost per unit of product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9874cb78-6865-4a31-931c-736f0979d3e8%2Fd11d2e8d-98b3-4e62-aa05-20e76446d01b%2Fgdkb3jc_processed.png&w=3840&q=75)
Transcribed Image Text:Question 3.
A cemented carbide tool is used to turn a part with length = 18.0 in and diameter = 3.0
in. The parameters in the Taylor equation are: n= 0.27 and C = 1200. The rate for the
operator and machine tool = $33.00/hr, and the tooling cost per cutting edge = $2.00.
It takes 3.0 min to load and unload the workpart and 1.50 min to change tools. The feed
= 0.013 in/rev. Determine:
a) Cutting speed for maximum production rate,
b) Tool life in min of cutting, and
c) Cycle time and cost per unit of product.
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