Question 29 of 30 Consider the reaction of N2O and O2 described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 NO(g) +3 O₂(g) 4 NO2(g) 1 2 NEXT > A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react at 298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products.. 2N₂O(g) + 302(g) == 4NO2(g) Initial (M) 0.200 -0.0100 0.190 Change (M) 0.0560 -0.0150 0.0410 Equilibrium (M) 0 0.0200 0.0200 RESET 0 0.0560 0.200 -1.00 -0.0560 0.0200 -0.0200 0.0100 -0.0100 -0.0050 0.0050 0.0150 -0.0150 0.210 0.190

Chemistry
10th Edition
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Question 29 of 30
Consider the reaction of N2O and O2 described by the chemical reaction below.
Determine the equilibrium constant for this reaction by constructing an ICE table,
writing the equilibrium constant expression, and solving it. Complete Parts 1-2
before submitting your answer.
2 NO(g) +3 O₂(g) 4 NO2(g)
1
2
NEXT >
A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react at
298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and
products..
2N₂O(g)
+
302(g)
==
4NO2(g)
Initial (M)
0.200
-0.0100
0.190
Change (M)
0.0560
-0.0150
0.0410
Equilibrium (M)
0
0.0200
0.0200
RESET
0
0.0560
0.200
-1.00
-0.0560
0.0200
-0.0200
0.0100
-0.0100
-0.0050
0.0050
0.0150
-0.0150
0.210
0.190
Transcribed Image Text:Question 29 of 30 Consider the reaction of N2O and O2 described by the chemical reaction below. Determine the equilibrium constant for this reaction by constructing an ICE table, writing the equilibrium constant expression, and solving it. Complete Parts 1-2 before submitting your answer. 2 NO(g) +3 O₂(g) 4 NO2(g) 1 2 NEXT > A 1.00 L reaction vessel was filled with 0.0560 mol O2 and 0.200 mol N2O and allowed to react at 298 K. At equilibrium, there were 0.0200 mol of NO2 present. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products.. 2N₂O(g) + 302(g) == 4NO2(g) Initial (M) 0.200 -0.0100 0.190 Change (M) 0.0560 -0.0150 0.0410 Equilibrium (M) 0 0.0200 0.0200 RESET 0 0.0560 0.200 -1.00 -0.0560 0.0200 -0.0200 0.0100 -0.0100 -0.0050 0.0050 0.0150 -0.0150 0.210 0.190
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