A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established: 2 NO + 2 H₂(g) = N2(g) + 2 H₂O(g) At equilibrium [NO] = 0.030 M. The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0. Calculate the equilibrium concentrations (in M) of: More Information X H₂(g) XN₂ (g) X H₂O (g) Question Answer Your answer -.020 is Your answer .035 is in Your answer .170 is i Tol: 0.0001 Tol: 0.001 Tol: ±0.001
A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established: 2 NO + 2 H₂(g) = N2(g) + 2 H₂O(g) At equilibrium [NO] = 0.030 M. The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0. Calculate the equilibrium concentrations (in M) of: More Information X H₂(g) XN₂ (g) X H₂O (g) Question Answer Your answer -.020 is Your answer .035 is in Your answer .170 is i Tol: 0.0001 Tol: 0.001 Tol: ±0.001
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established:
+ 2 H₂ (g) = N2(g) + 2 H₂O (g)
2 NO
At equilibrium [NO] = 0.030 M.
The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0.
Calculate the equilibrium concentrations (in M) of:
More Information
X H₂ (g)
XN₂ (g)
X H₂O (g)
Question
Answer
Your answer -.020 is
Your answer .035 is in
Your answer .170 is i
Tol: 0.0001
Tol: 0.001
Tol: 0.001](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F706fa0bc-8b2b-46b5-9a0a-aff6b909f26f%2Fb66a0d74-2131-4f74-9af2-b8f0f890ced3%2Fo0wn1a_processed.png&w=3840&q=75)
Transcribed Image Text:A mixture of 0.10 mole NO, 0.050 mole H₂, and 0.10 mole H₂O is placed in a 2.0 L vessel. The following equilibrium is established:
+ 2 H₂ (g) = N2(g) + 2 H₂O (g)
2 NO
At equilibrium [NO] = 0.030 M.
The initial concentration of N₂ was not mentioned so you must assume [N₂] = 0.
Calculate the equilibrium concentrations (in M) of:
More Information
X H₂ (g)
XN₂ (g)
X H₂O (g)
Question
Answer
Your answer -.020 is
Your answer .035 is in
Your answer .170 is i
Tol: 0.0001
Tol: 0.001
Tol: 0.001
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