Use this information to answer Questions 3, 4, and 5: The equilibrium constant (K) of the reaction below is K = 6.0 x 102, with initial concentrations as follows: [H2) = 1.0 x 102 M, [N2] = 4.0 M, and [NH3] = 1.0 x 10“ M. N2(g) + 3H2(g) = 2NH3(g) 3. BI U O Word(s) 4. If the concentration of the reactant H2 was decreased from 1.0x 102 M to 2.7 x 104 M, calculate the reaction quotient (Q) and determine which way the chemical system would shift by comparing the value of Q to K. BI U E T T, O Word(s) !! !!!

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Chapter1: Chemical Foundations
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Use this information to answer Questions 3, 4, and 5:
The equilibrium constant (K) of the reaction below is K = 6.0 x 10-2, with initial concentrations as follows:
[H2] = 1.0 x 102 M, [N2] = 4.0 M, and [NH3] = 1.0 x 104M.
N2(g) + 3H2(g) = 2NH3(g)
3.
BI U
T
O Word(s)
4. If the concentration of the reactant H2 was decreased from 1.0 x 10-² M to 2.7 x 10-4 M, calculate the reaction
quotient (Q) and determine which way the chemical system would shift by comparing the value of Q to K.
BI U
T
O Word(s)
Transcribed Image Text:Use this information to answer Questions 3, 4, and 5: The equilibrium constant (K) of the reaction below is K = 6.0 x 10-2, with initial concentrations as follows: [H2] = 1.0 x 102 M, [N2] = 4.0 M, and [NH3] = 1.0 x 104M. N2(g) + 3H2(g) = 2NH3(g) 3. BI U T O Word(s) 4. If the concentration of the reactant H2 was decreased from 1.0 x 10-² M to 2.7 x 10-4 M, calculate the reaction quotient (Q) and determine which way the chemical system would shift by comparing the value of Q to K. BI U T O Word(s)
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