Q28 Please provide justified answer asap to get a upvote AIl Crcies are toe circies.For B<53°:Toe circle -Midpoint circleDH---.E nHSlope circle -----Firm layer(a)0.30.24.00.1908070605040302010Slope angle. B(deE)(b)Figran 13.8 (a) Definition of parameters for milpint circlelype failure; (b) plot of stability number against slopeangle (Soil Mechanies in Engincering Practice. Terzaghi and Peck, 1967. John Wiley & Sons, Inc, Redrawn withpennission of John Wiley & Sons, Inc.)cslScanned with CamScannerStability number, m Question 28A cut is to be made in a saturated clay, as shown in the figure below. The cut slope willmaintain an angle of 60 degrees with the horizontal. The clay has the undrained shearstrength, Cu=40 kPa, Y sat=18.5 kN/m3, and Ou = 0 kPa.How deep is the cut if the factor of safety of 1.5 against sliding is required ? Unit: mFor B>53°:All circles are toe circles.For B<53°:Toe circle- -Midpoint circle -.DHSlope circle -----Fim layer(a)0.30.24.00.1CSScanned with CamScannerStability number, m

Answered: Image /qna-images/answer/4204ae0f-421d-4aa1-9a25-e9e3019093c5.jpg

Question 26 A cut is to be made in a saturated clay, as shown in the figure below. The cut slope will maintain an angle of 60 degrees with the horizontal. The clay has the undrained shear strength, Cu=40 kPa, Ysat=18.5 kN/m3, and u = 0 kPa. How deep is the cut if the factor of safety of 1.5 against sliding is required ? Unit: m For B>53°: All circles are toe circles. For B<53°: Toe circle Midpoint circle --. DH Slope circle----- nH Fim layer (a) 0.3 0.2 0.1 CS Scanned with Camleanner Stability number, m

Question 26 A cut is to be made in a saturated clay, as shown in the figure below. The cut slope will maintain an angle of 60 degrees with the horizontal. The clay has the undrained shear strength, Cu=40 kPa, Ysat=18.5 kN/m3, and u = 0 kPa. How deep is the cut if the factor of safety of 1.5 against sliding is required ? Unit: m For B>53°: All circles are toe circles. For B<53°: Toe circle Midpoint circle --. DH Slope circle----- nH Fim layer (a) 0.3 0.2 0.1 CS Scanned with Camleanner Stability number, m

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter15: Slope Stability

Section: Chapter Questions

Problem 15.17P

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X=35 Y=30 Z=19.5
Subject : Geotechnical Engineering Give me right solution according to the question. A 6m vertical cut has been excavated from a dry cohesive loess soil deposit. For the plane shown passing through the vertical cut face, estimate whether or not a shear failure is likely.
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A cut slope is to be excavated in saturated clay with sides rising at an angle a = 55° to the horizontal, as shown below B Saturated Clay Ysat = 115 Ib/ft Unconfined Compressive Strength q,= 1000 Ib/ft? a = 55°, B = 35° H. B A a. The depth H of the excavation for a factor of safety of 1 when considering the trial failure plane AC is ft. b. The depth H of the excavation for a factor of safety of 1 when considering the most critical failure plane is ft.
O DrahmedsoilMechanicsnoteschapter5.pdf s/DrahmedsoilMechanicsnoteschapter5.pdf A V - 14 A 10-m-thick layer of stiff saturated clay is underlain by a layer of sand. The sand is under artesian pressure. A 5.75-m-deep cut is made in the clay. What would be the maximum permissible depth of cut before heaving would occur. Determine the factor of safety against heaving at point A. Ans.: H =6.88m, FOS = 1.36 P = 1925 kg/m 5.75 m 10 m Saturated clay 6 m Sand Par - 1840 kg/m 2.5 m Soil Mechanics Assistant Prof. Dr. Ahmed Al-Obaidi Civil Eng Dept - College of Eng. (173) 5.15 Refer to Problem 5.14. Water may be introduced into the cut to improve
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Answer Q13 to Q 15 based on following description A cutting in a saturated clay is inclined at a slope 1 vert:1.2 horizontal and has a vertical height of 10.0 m. The bulk unit weight of the soil is 18 kN/m³ and its undrained cohesion is 35 kN/m³. Undrained friction angle, -0. Area of slip mass = 51.2 m², d= 7 m r=12m 2m 1 W 10m FoS of a slope along a circular slip surface is given by; cular F = Wd Calculate the arc length along the slip surface, La a-964.8 m O b. 16.8 m O c. 114.0 m O d. 8.4 m d=5m 1.2
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A cutting is made in clay y=20kN/m³, ¤ =0, c = 35 kN/m2. Take FOS= 1.5 and Sn = 0.17. Maximum depth of cutting will be, 5.86 10.29 m 6.86 m 9.29
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(a) Calculate the area of the joint and the weight of the wedge (W) in MN assuming a unit length along the out of plane direction (normal to the plane of the figure). (b) Calculate the normal force (N) on the joint plane before and after excavation. (C) Calculate the shear force (T) on the joint plane before and after excavation. d) Calculate the frictional shear strength force (S¢) on the joint plane before and after excavation. (e) Calculate the cohesive shear strength force (Sc) on the joint plane before and after excavation. (f)Calculate the total shear strength force (S = Sc + So) on the joint plane before and after excavation. (g) Calculate the partial factor of safety before and after excavation () due to friction only (FoS¢), (i) due to cohesion only (FoSc), (iii) total factor of safety due to both friction and cohesion ((FoS= FoSc+ FoS). (h) Determine dip, dip direction, strike and pole of both planes (slope and joint planes). Discuss the stability of the wedge against…