Two cylindrical rods, AC made of aluminum and CD made of steel, are joined at Cand restrained by rigid supports at A and D. It is given that E = 10.4 x 10° psi, E₂=29 x 10° psi, and P=20 kips. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 8in10 in 10 in A 1-in. diameter 14 kips 1-in. diameter Determine the reactions at A and D. The reaction at A is The reaction at Dis kips.. kips- Required information

Two cylindrical rods, AC made of aluminum and CD made of steel, are joined at Cand restrained by rigid supports at A and D. It is given that E = 10.4 x 10° psi, E₂=29 x 10° psi, and P=20 kips. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 8in10 in 10 in A 1-in. diameter 14 kips 1-in. diameter Determine the reactions at A and D. The reaction at A is The reaction at Dis kips.. kips- Required information

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The figure shows a cutaway view of an assembly in which a solid bronze [G = 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d1 = 2.05 in. The outside diameter of the tube is D2 = 2.8 in. and its wall thickness is t2 = 0.110 in. Overall dimensions of the assembly are a = 55 in. and b = 11 in. The allowable shear stresses for the bronze and aluminum materials are 10800 psi and 7800 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 4.8°. Based on these constraints, what is the maximum torque TB that can be applied at end B?
The figure shows a cutaway view of an assembly in which a solid bronze [G= 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d₁ = 1.15 in. The outside diameter of the tube is D₂ = 3.4 in. and its wall thickness is t₂ = 0.130 in. Overall dimensions of the assembly are a = 50 in. and b = 14 in. The allowable shear stresses for the bronze and aluminum materials are 10600 psi and 7600 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 4.3°. Based on these constraints, what is the maximum torque Te that can be applied at end B? Fixed End plate 12 plate TB Rod (1) A Tube (2) W a D2 Answer: TB = lb-in b B
The figure shows a cutaway view of an assembly in which a solid bronze [G = 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d1 = 1.45 in. The outside diameter of the tube is D2 = 3.2 in. and its wall thickness is t2 = 0.140 in. Overall dimensions of the assembly are a = 42 in. and b = 6 in. The allowable shear stresses for the bronze and aluminum materials are 10700 psi and 8100 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 5.9°. Based on these constraints, what is the maximum torque TB that can be applied at end B?
The figure shows a cutaway view of an assembly in which a solid bronze [G = 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d1 = 1.75 in. The outside diameter of the tube is D2 = 2.7 in. and its wall thickness is t2 = 0.130 in. Overall dimensions of the assembly are a = 38 in. and b = 13 in. The allowable shear stresses for the bronze and aluminum materials are 9400 psi and 7500 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 5.1°. Based on these constraints, what is the maximum torque TB that can be applied at end B?
The figure shows a cutaway view of an assembly in which a solid bronze [G = 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d1 = 1.85 in. The outside diameter of the tube is D2 = 2.9 in. and its wall thickness is t2 = 0.160 in. Overall dimensions of the assembly are a = 41 in. and b = 15 in. The allowable shear stresses for the bronze and aluminum materials are 10000 psi and 8000 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 4.8°. Based on these constraints, what is the maximum torque TB that can be applied at end B?
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The figure shows a cutaway view of an assembly in which a solid bronze [G= 6,500 ksi] rod (1) is fitted inside of an aluminum alloy [G = 4,000 ksi] tube (2). The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at A. The rod diameter is d₁ = 1.55 in. The outside diameter of the tube is D₂ = 2.8 in. and its wall thickness is t₂ = 0.115 in. Overall dimensions of the assembly are a = 35 in. and b = 11 in. The allowable shear stresses for the bronze and aluminum materials are 9800 psi and 8500 psi, respectively. Further, the rotation angle of end B must be limited to a magnitude of 4.2°. Based on these constraints, what is the maximum torque Tg that can be applied at end B? Fixed End plate plate di TB Rod (1) D₂ Answer: TB = A Tube (2) a lb-in b B
Mechanics . I need the answer asap thank you
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Three solid cylindrical rods are welded together to form the compound axial member shown in the figure. The compound axial member is attached to a fixed support at A. Each rod has an elastic modulus of E = 47 GPa. Use the following values for the rod lengths and areas: L₁ = 1350 mm, L₂ = 1760 mm, L3 = 1300 mm, A₁ = 260 mm², A₂ = 155 mm², and A3 = 80 mm². What magnitude of external load Pis needed to displace end D a distance of up = 30 mm to the right? Part 1 8₁ F₁ = Part 2 8₂ F2 A = L₁ mm/kN (1) B L2 (2) Find the relationship between ₁, the elongation of rod (1), and the internal tensile force, F₁, in rod (1). Assume 8, is a positive value in units of mm and F, is a positive value in units of kN. So, the answer you enter for the ratio (8₁/F₁) must be in units of (mm/kN). mm/kN C L3 (3) D Similar to the previous step, find the relationship between 82, the elongation of rod (2), and the internal tensile force, F2, in rod (2). Assume 82 is a positive value in units of mm and F2 is a…
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