Q5. (P.) A 30 m height slope is to be built as shown below. The homogeneous with c' = X kN/m² and o' =Y°. The saturated unit weight of soil is Z kN/m³. Using the ordinary method of slices, compute the factor of safety along the potential failure surface. In your calculations, you should also consider the seven meter depth tension crack [GWT at ground surface]. (FScheck =2.0 and yw= 10 kN/m³). Last digit of school number 1 3 4 5 6 7 8 X= 15 X= 20 X= 25 X= 30 X= 35 X= 40 X= 45 X= 50 X= 55 X= 60 Y= 38 Y= 36 Y= 34 Y= 32 Y= 30 Y= 28 Y= 26 Y= 24 Y= 22 Y= 20 Z = 17.5 Z = 18 Z = 18.5 Z= 19 Z = 19.5 Z= 20 Z=20.5 Z= 21 Z = 21.5 Z= 22 10.8 9.4 12.1 12.7 9.3 7.6 i 7.0 30.0 a = 53 a= 38 a= 24 a = -18 a= 8 a=-7 No b (m) hi (m) h2 (m) a (°) 1 10.8 10.3 -18 2 9.4 10.3 17.7 -7 3 12.1 17.7 24.6 8 4 12.7 24.6 25.9 24 5 9.3 25.9 22.5 38 6 7.6 22.5 53
Q5. (P.) A 30 m height slope is to be built as shown below. The homogeneous with c' = X kN/m² and o' =Y°. The saturated unit weight of soil is Z kN/m³. Using the ordinary method of slices, compute the factor of safety along the potential failure surface. In your calculations, you should also consider the seven meter depth tension crack [GWT at ground surface]. (FScheck =2.0 and yw= 10 kN/m³). Last digit of school number 1 3 4 5 6 7 8 X= 15 X= 20 X= 25 X= 30 X= 35 X= 40 X= 45 X= 50 X= 55 X= 60 Y= 38 Y= 36 Y= 34 Y= 32 Y= 30 Y= 28 Y= 26 Y= 24 Y= 22 Y= 20 Z = 17.5 Z = 18 Z = 18.5 Z= 19 Z = 19.5 Z= 20 Z=20.5 Z= 21 Z = 21.5 Z= 22 10.8 9.4 12.1 12.7 9.3 7.6 i 7.0 30.0 a = 53 a= 38 a= 24 a = -18 a= 8 a=-7 No b (m) hi (m) h2 (m) a (°) 1 10.8 10.3 -18 2 9.4 10.3 17.7 -7 3 12.1 17.7 24.6 8 4 12.7 24.6 25.9 24 5 9.3 25.9 22.5 38 6 7.6 22.5 53
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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X=35 Y=30 Z=19.5
![Q5. (P.) A 30 m height slope is to be built as shown below. The homogeneous with c' = X kN/m² and o' = Y°.
The saturated unit weight of soil is Z kNhm³. Using the ordinary method of slices, compute the factor of safety
along the potential failure surface. In your calculations, you should also consider the seven meter depth tension
crack [GWT at ground surface]. (FScheck = 2.0 and yw= 10 kN/m³).
Last digit of school number
1
3
4
5
7
8
9
X= 15
X= 20
X= 25
X= 30
X= 35
X= 40
X= 45
X= 50
X= 55
X= 60
Y= 38
Y= 36
Y= 34
Y= 32
Y= 30
Y= 28
Y= 26
Y= 24
Y= 22
Y= 20
Z = 17.5 Z= 18 Z = 18.5
Z = 19
Z = 19.5
Z = 20
Z =20.5
Z 21
Z = 21.5
Z = 22
10.8 9.4 12.1 12.7 9.3 7.6
7.0
30.0
a = 53
a= 38
α 24
a = -18
a = 8
a = -7
No b (m) hi (m) | h2 (m) a (°)
1
10.8
10.3
-18
2
9.4
10.3
17.7
-7
3
12.1
17.7
24.6
8
4
12.7
24.6
25.9
24
5
9.3
25.9
22.5
38
6
7.6
22.5
53](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F125b69fe-8768-4baa-8055-01d630864aa8%2F67ecfafc-234e-4b51-9b40-8c258f14dd3d%2F31tqu3_processed.png&w=3840&q=75)
Transcribed Image Text:Q5. (P.) A 30 m height slope is to be built as shown below. The homogeneous with c' = X kN/m² and o' = Y°.
The saturated unit weight of soil is Z kNhm³. Using the ordinary method of slices, compute the factor of safety
along the potential failure surface. In your calculations, you should also consider the seven meter depth tension
crack [GWT at ground surface]. (FScheck = 2.0 and yw= 10 kN/m³).
Last digit of school number
1
3
4
5
7
8
9
X= 15
X= 20
X= 25
X= 30
X= 35
X= 40
X= 45
X= 50
X= 55
X= 60
Y= 38
Y= 36
Y= 34
Y= 32
Y= 30
Y= 28
Y= 26
Y= 24
Y= 22
Y= 20
Z = 17.5 Z= 18 Z = 18.5
Z = 19
Z = 19.5
Z = 20
Z =20.5
Z 21
Z = 21.5
Z = 22
10.8 9.4 12.1 12.7 9.3 7.6
7.0
30.0
a = 53
a= 38
α 24
a = -18
a = 8
a = -7
No b (m) hi (m) | h2 (m) a (°)
1
10.8
10.3
-18
2
9.4
10.3
17.7
-7
3
12.1
17.7
24.6
8
4
12.7
24.6
25.9
24
5
9.3
25.9
22.5
38
6
7.6
22.5
53
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