Determine the location (x, y) of the centroid of the area. 2 in. 2 in. 4 in. C 4 in. y T 2in + cin 2inuin C A I 2 in. PS: Hints are given in lecture notes on Canvas. ート X 2in A = 2(2+4) = 12 in 2 Area: L.W. = A = B = 2(2+4)= 12 in 2 - C = 214) = 8 in 2 B tx + り Segment A (in²) x (in) 5 (in) x. A lin³) 5.A (in³) 2/2+4) (2+4)/2 A 3(12) 12 3 36 B 2/2+4) (2+4)/2 3(12) 12 3 36 C 2(u) 2/2 1(8) 8 1 8 Σ 32 80 Σ x= 2 (x. Area) = 202 Z Aren 5 = Σ (5. Area) 80 32 = 2.5 Area 32
Determine the location (x, y) of the centroid of the area. 2 in. 2 in. 4 in. C 4 in. y T 2in + cin 2inuin C A I 2 in. PS: Hints are given in lecture notes on Canvas. ート X 2in A = 2(2+4) = 12 in 2 Area: L.W. = A = B = 2(2+4)= 12 in 2 - C = 214) = 8 in 2 B tx + り Segment A (in²) x (in) 5 (in) x. A lin³) 5.A (in³) 2/2+4) (2+4)/2 A 3(12) 12 3 36 B 2/2+4) (2+4)/2 3(12) 12 3 36 C 2(u) 2/2 1(8) 8 1 8 Σ 32 80 Σ x= 2 (x. Area) = 202 Z Aren 5 = Σ (5. Area) 80 32 = 2.5 Area 32
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Determine the location of the centroid of the area.
Segments A,B, and C. I can't figure how to find y.
Transcribed Image Text:Determine the location (x, y) of the centroid of the area.
2 in.
2 in.
4 in.
C
4 in.
y
T
2in
+
cin
2inuin
C
A
I
2 in.
PS: Hints are given in lecture notes on Canvas.
ート
X
2in
A = 2(2+4) = 12 in 2
Area: L.W. = A =
B = 2(2+4)= 12 in 2
-
C = 214) = 8 in 2
B
tx +
り
Transcribed Image Text:Segment A (in²) x (in) 5 (in) x. A lin³) 5.A (in³)
2/2+4) (2+4)/2
A
3(12)
12
3
36
B
2/2+4) (2+4)/2
3(12)
12
3
36
C
2(u)
2/2
1(8)
8
1
8
Σ
32
80
Σ
x= 2 (x. Area) = 202
Z Aren
5 = Σ (5. Area)
80
32
= 2.5
Area
32
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