Answer Q13 to Q 15 based on following description A cutting in a saturated clay is inclined at a slope 1 vert:1.2 horizontal and has a vertical height of 10.0 m. The bulk unit weight of the soil is 18 kN/m³ and its undrained cohesion is 35 kN/m³. Undrained friction angle, 4 -0. Area of slip mass = 51.2 m², d= 7m 12m 2m 1 10m FoS of a slope along a circular slip surface is given by; CuLar F = Wd Calculate the arc length along the slip surface, La O a-964.8 m O b. 16.8 m O c. 114.0 m O d.g.4 m d=5m 1.2 W

Q: 3. Point A lies in a clayey sand layer with ' = 38, c' = 10 kPa, and Ko = 0.5. The ground surface is…

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Q: Ox (psi) 2000 To (Cohesion) (psi) 1000 50 Oy (psi) 1800 (Internal friction angle), º Po (psi) 1000…

A: Given; = 2000 psi σy = 1800 psi Po = 1000 psi

Q: 43. A footing 3 m x 3 m (10 ft x 10 ft) is designed to carry a 200-tonne (220-ton) load. Find the…

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Q: . The undrained cohesion of a remoulded clay soil is 10 kN/m². If the sensitivity of the clay is 20,…

A: Undrained cohesion C=10 kN/m2,Sensitivity of clay S=20,The value of the remoulded compressive…

Q: The major principal stress (kPa) on the soil element is (anti-clockwise shear +ve) 100 kPa 50 kPa…

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Q: Foundation 3 m x 4.5 m 4.5 m Load 2025 kN -1.5 m- Determine the -3 m- increasing of vertical stress…

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Q: a) In a deposit of normally consolidated sand, 6 m thick, the average SPT N value is 16. The water…

A: { NOTE - According to Bartleby Guidelines, we are directed to solve only one question at one time.…

Q: excavation of a certain foundation pit, draining water causes upward seepage. The water head…

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Q: A 2 mx 5 m rectangular area carrying a uniform load of 145 kPa is applied to the ground surface.…

A: Vertical stress are defined as the force per unit area.  These types of stresses focuses on the  1.…

Q: Circular foundation diameter B = 2m G.S. 1.0m Sand q = 150 kN/m² y = 17 kNhm² 0.5m W.T. Sand 0.5m 7…

A: Given data-

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.