Circular foundation diameter B = 2m G.S. 1.0m Sand q = 150 kN/m² y = 17 kNhm² 0.5m W.T. Sand 0.5m 7 sat. 5 19 kNhm? Normally consolidated clay Y sat. = 18.5 kN/m Cc =0.16, e, =0.85 5.0m
Circular foundation diameter B = 2m G.S. 1.0m Sand q = 150 kN/m² y = 17 kNhm² 0.5m W.T. Sand 0.5m 7 sat. 5 19 kNhm? Normally consolidated clay Y sat. = 18.5 kN/m Cc =0.16, e, =0.85 5.0m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
A circular foundation 2m in diameter is shown in the figure below. A normally
consolidated clay layer 5m thick is located below the foundation. Determine the consolidation settlement of the clay.
1- method 2:1
2- consolidation settlement Cc method
![Circular foundation
diameter B = 2m
G.S.
1.0m
Sand
q = 150 kN/m²
y = 17 kN/m²
0.5m
W.T.
Sand
0.5m
Ysat. 19 kNhn?
Normally consolidated clay
Y sat. = 18.5 kN/m²
Cc =0.16, e, =0.85
5.От](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F76ebb5cc-d9dc-4d72-b540-96a3eafd4a05%2Fb94968d6-4d69-4efa-a49d-bdc84c2db3a5%2Fpu829lf_processed.png&w=3840&q=75)
Transcribed Image Text:Circular foundation
diameter B = 2m
G.S.
1.0m
Sand
q = 150 kN/m²
y = 17 kN/m²
0.5m
W.T.
Sand
0.5m
Ysat. 19 kNhn?
Normally consolidated clay
Y sat. = 18.5 kN/m²
Cc =0.16, e, =0.85
5.От
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